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oksano4ka [1.4K]
3 years ago
9

Turn 4/10 into mixed radical

Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

its 2.4332

Step-by-step explanation:

look at answer

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6x – 2х + 8у – 6y simplified expression
Sholpan [36]

Answer:

4x+2y

Step-by-step explanation:

5 0
3 years ago
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A ladder is leaning against the house. The base of the ladder is 9 feet from the base of the house. The ladder is 20 feet long.
zvonat [6]

Answer:

17.86057

Step-by-step explanation:

4 0
3 years ago
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The battery on McKenzies old computer can last 4(1/5) hours. She bought a new computer that has a battery that can last 40% long
Solnce55 [7]

Answer:

5\frac{22}{25}\ hours

Step-by-step explanation:

we know that

4\frac{1}{5}\ hours=\frac{4*5+1}{5}=\frac{21}{5}\ hours

100\%+40\%=140\%=\frac{140}{100}

Let

x ------> new battery life

The equation that represent this situation is

x=\frac{140}{100} (\frac{21}{5})=\frac{2,940}{500}\ hours

convert to mixed number

\frac{2,940}{500}=\frac{2,500}{500}+\frac{440}{500}=5\frac{22}{25}\ hours

4 0
3 years ago
John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart
Rina8888 [55]
<h2>Answer:</h2>

Probability=\frac{1}{24}

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is \frac{1}{24}</u></em>

3 0
3 years ago
F(x)=x find the graph of f(x)+3
Anastasy [175]
Given that f(x) = x.
Then f(x) + 3 is the graph of f(x) translated 3 units up.
8 0
3 years ago
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