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djverab [1.8K]
3 years ago
6

Need help ASAP ITS DUE Soon???!!!

Mathematics
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

V=942.5

Step-by-step explanation:

V=(π)(r)^2(h)

V= (π)(10/2)^2(12)

V=942.5

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Factorization of 3x2-8x-3
pychu [463]
<span>3x</span>² <span>- 8x -3  = 3x</span>² - 9x + x - 3 =

= 3x² - 9x + x - 3 = 3x* ( x - 3) + 1* (x - 3) = 

= 3x * (x - 3) + 1 * (x - 3) = (3x + 1) (x - 3) 

Answer (3x + 1) (x - 3)

3 0
3 years ago
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N which number does the digit 5 have a value that is ten times greater than the value of the digit 5 in the number 245,093?
OLEGan [10]

Answer:

53,901

Step-by-step explanation:

Here is the complete question :

In which number does the digit 5 have a value that is ten times greater than the value of the digit 5 in the number 245,093?

43,567

45,248

53,901

562,011

In the number 245,093 :

3 = units

9 = tens

0 = hundred

5 = thousand

4 = ten thousand

2 = hundred thousand

the value of 5 in the number is 5000. the number that would have a value that it 10 times greater than 5 in 245,093 must occupy the value  of ten thousand.

looking through the options, it is only in 53,901 that 5 occupies a value of ten thousand

6 0
3 years ago
PLS PLS HELP SO
pickupchik [31]
If your average speed is 2.05 and your time is the average of .87+.94+.72=0.843 then your answer should be 1.728 because distance= speed x time. I don’t know if this is correct because you didn’t label what the numbers were but I hope this helped you!! :)
3 0
2 years ago
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You’re working in the sedan section of dean’s car dealership. A customer makes a down payment of 15% on a new car that costs $13
Shkiper50 [21]

Answer:

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3 0
3 years ago
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
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