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Juli2301 [7.4K]
3 years ago
12

Please help i will give metal.

Mathematics
1 answer:
Nataliya [291]3 years ago
4 0
It would be either A or D because it says that john has 3 rows and does not say of how many stickers...but Raj have 36 stickers and Tajika has 36 stickers and Sue Lee has 40 so it would either A or D
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Determine if the equation 2x=y represents a proportional relationship.
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Proportional Relationships

A proportional relationship is one in which two quantities vary directly with each other. We say the variable y varies directly as x if:

y=kx

for some constant k , called the constant of proportionality .

(Some textbooks describe a proportional relationship by saying that " y varies proportionally with x " or that " y is directly proportional to x .")

This means that as x increases, y increases and as x decreases, y decreases-and that the ratio between them always stays the same.

The graph of the proportional relationship equation is a straight line through the origin.

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2 years ago
P•3 then add 1/6 of the amount
Black_prince [1.1K]
3*P + (1/6%* 3p)=

Thats the formula

basically its: 3 * p + 1/6 of 3p



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The number of hours a group of 12 children in Mrs. Smith's kindergarten class read in a day.
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Suppose a and b are the solutions to the quadratic equation 2x^2-3x-6=0. Find the value of (a+2)(b+2).
KonstantinChe [14]

Answer:

(a+2)(b+2) = 4

Step-by-step explanation:

We are given the following quadratic equation:

2x^2-3x-6=0

Let a a and b be the solution of the given quadratic equation.

Solving the equation:

2x^2-3x-6=0\\\text{Using the quadratic formula}\\\\x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{Comparing the equation to }ax^2 + bx + c = 0\\\text{We have}\\a = 2\\b = -3\\c = -6\\x = \dfrac{3\pm \sqrt{9-4(2)(-6)}}{4} = \dfrac{3\pm \sqrt{57}}{4}\\\\a = \dfrac{3+\sqrt{57}}{4}, b = \dfrac{3-\sqrt{57}}{4}

We have to find the value of (a+2)(b+2).

Putting the values:

(a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4

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3 years ago
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