All categories

3 years ago

Please help i will give metal.

1 answer:

4 0

It would be either A or D because it says that john has 3 rows and does not say of how many stickers...but Raj have 36 stickers and Tajika has 36 stickers and Sue Lee has 40 so it would either A or D

You might be interested in

What's the answer do this question??

Gemiola [76]

It is A) skewed left because the long tail in the box plot is on the left hand side. The mean is also on the left hand side of the peak so it is skewed left.

Hope this helps :)

4 0

3 years ago

ANSWER THIS!!! Please?

KIM [24]

x is a variable. You need to find the variable to complete the equation.

ex. x = 1

x to the power of 5 (1x5x5x5x5x5)

1*x(0)=0

7 0

3 years ago

Which polynomial expression represents a sum of cubes? (6 – s)(s2 + 6s + 36) (6 + s)(s2 – 6s – 36) (6 + s)(s2 – 6s + 36) (6 + s)

Nadusha1986 [10]

Answer:

Option 3 is correct that is $(6+s)(s^2-6s+36)$

Step-by-step explanation:

We have general formula for sum of cube which is

$a^3+b^3=(a+b)(a^2+b^2-ab)$

Here, we have a=s and b=6

on substituting the values in the formula we will get

$6^3+s^3=(6+s)(s^2+6^2-6s)$

After simplification we will get

$6^3+s^3=(6+s)(s^2+36-6s)$

After rearranging the terms we will get

$6^3+s^3=(6+s)(s^2-6s+36)$ which exactly matches option 3 in the given options.

Therefore, option 3 is correct that is $(6+s)(s^2-6s+36)$

4 0

3 years ago

Read 2 more answers

Find the tangent line approximation for 10+x−−−−−√ near x=0. Do not approximate any of the values in your formula when entering

Svetllana [295]

Answer:

$L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$

Step-by-step explanation:

We are asked to find the tangent line approximation for $f(x)=\sqrt{10+x}$ near $x=0$ .

We will use linear approximation formula for a tangent line $L(x)$ of a function $f(x)$ at $x=a$ to solve our given problem.

$L(x)=f(a)+f'(a)(x-a)$

Let us find value of function at $x=0$ as:

$f(0)=\sqrt{10+x}=\sqrt{10+0}=\sqrt{10}$

Now, we will find derivative of given function as:

$f(x)=\sqrt{10+x}=(10+x)^{\frac{1}{2}}$

$f'(x)=\frac{d}{dx}((10+x)^{\frac{1}{2}})\cdot \frac{d}{dx}(10+x)$

$f'(x)=\frac{1}{2}(10+x)^{-\frac{1}{2}}\cdot 1$

$f'(x)=\frac{1}{2\sqrt{10+x}}$

Let us find derivative at $x=0$

$f'(0)=\frac{1}{2\sqrt{10+0}}=\frac{1}{2\sqrt{10}}$

Upon substituting our given values in linear approximation formula, we will get:

$L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}(x-0)$

$L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}x-0$

$L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$

Therefore, our required tangent line for approximation would be $L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$ .

8 0

2 years ago

The position of a digit in a number that determines its value

Maslowich

So in long numbers or any number the positon determines its in the ones, tenths, hundredths

e.g
658
6 is in the hundredths as it is technically 600
5 is in the tenths as it is 50
8 is the ones as its just 8

4 0

3 years ago