When graphs are plotted, graphs as in the .jpeg image in attachment are obtained.
First graph is line going through ordered pair (point) (0,6) and pair (6,8).
The second graph is line going through ordered pair (6,8) and pair (8,0).
Intercept of these graphs is point (ordered pair) (6,8).
You see from the .jpeg image that the following is true:
Initial velocity of the runner is 6 meters per second (runner starts with this velocity), for a while he runs, velocity grows, then in the 6th second (time=6), runner starts to slow down and velocity starts to decrease, and runner stops totally at time = 8.
So runner stops after 8 seconds.
The 4th claim (sentence) is correct.
Answer:
parellel planes do not intersect
non-coplanar also dont
They are extremely similar but a(x) has a greater y-intercept!
If you look at the y axis, a(x) simply intercept it higher than b(x)
Hope this helps!
It would reflect over the x-axis and then reflect over the y-axis
Answer:
![\tan \theta](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta)
Step-by-step explanation:
We have to simplify the following expression as given by
![\sin \theta \times \sec \theta](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%20%5Ctimes%20%5Csec%20%5Ctheta)
= ![\frac{\sin \theta}{\cos \theta}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D)
=
( Answer )
Because, we know that
and ![\tan \theta = \frac{\sin \theta}{\cos \theta}](https://tex.z-dn.net/?f=%20%5Ctan%20%5Ctheta%20%3D%20%5Cfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D)
If we consider
and
,
then ![\sin \theta \times \sec \theta = \frac{Perpendicular}{Hypotenuse}\times \frac{Hypotenuse}{Base} = \frac{Perpendicular}{Base}= \tan \theta](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%20%5Ctimes%20%5Csec%20%5Ctheta%20%3D%20%5Cfrac%7BPerpendicular%7D%7BHypotenuse%7D%5Ctimes%20%5Cfrac%7BHypotenuse%7D%7BBase%7D%20%3D%20%5Cfrac%7BPerpendicular%7D%7BBase%7D%3D%20%5Ctan%20%5Ctheta%20)