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2 years ago

Simplify: (2 + 1)^2 Plz

2 answers:

8 0

We have to use the order of operations to solve this equation.

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

The equation:
(2+1)²

So first, let's do 2+1, since it's in parentheses and you have to do parentheses first in the order of operations.
2+1 = 3

Now all we have left is:
3²

Then exponents:
3² = 9

The answer is 9.

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)

Pavel [41]2 years ago

6 0

The answer is 9! Hope this helps!

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Find the area of

harina [27]

Answer:

1. 766,536cm^3

2. 29,680,948cm^3

3. 41,620.8cm^3

Step-by-step explanation:

1. 123×82 = 10,086 10,086×76 = 766,536

2. 422×278 = 117,316 117,316×253 = 29,680,948

3. 87×2.3 = 200.1 200.1×208 = 41,620.8

Hope this helps! :)

5 0

2 years ago

Rewrite without absolute value for the given conditions:<br><br> y=|x-5|+|x+5| if -5

Margaret [11]

Y=x+5+x+5
y=2x+10
there ya go :)

5 0

2 years ago

Shtirlitz [24]

B. is the correct ansew

3 0

2 years ago

What is the equation of the line that passes through the point (1,0) and is perpendicular to the line x+5y=30

Andre45 [30]

Answer:

The equation of line passing through points (1 , 0) is x - 5 y - 1 = 0

Step-by-step explanation:

Given equation of line as

x + 5 y = 30

Now, equation of line in standard form is y = m x + c

where m is the slope

So, x + 5 y = 30

Or, 5 y = - x + 30

Or, y = - $\frac{1}{5}$ x + 6

So, Slope of this line m = - $\frac{1}{5}$

Again , let the slope of other line passing through point (1 , 0) is M

And Both lines are perpendicular , So , products of line = - 1

i.e m × M = - 1

Or, M = - $\frac{1}{m}$

Or, M = - 1 × - $\frac{1}{\frac{1}{5}}$ = $\frac{1}{5}$

So, equation of line with slope M and points (1, 0) is

y - $y_1$ = M × (x - $x_1$ )

Or, y - ( 0 ) = $\frac{1}{5}$ × ( x - 1 )

Or, y = $\frac{1}{5}$ x - $\frac{1}{5}$ × 1

Or, y = $\frac{1}{5}$ x - $\frac{1}{5}$

or, y + $\frac{1}{5}$ = $\frac{1}{5}$ x

Or, 5×y + 1 = x

∴ 5 y + 1 = x

I.e x - 5 y - 1 = 0

Hence The equation of line passing through points (1 , 0) is x - 5 y - 1 = 0 Answer

7 0

2 years ago

Which equation represents a line that passes through (2,-1/2) and has a slope of 3 ?

Anna11 [10]

Answer:

C. $y + \frac{1}{2} = 3(x - 2)$

Step-by-step explanation:

Given

$Point: (2,\frac{-1}{2})$

$Slope: 3$

Required

Equation of line

Let m represents the slope of the line;

m is calculated as thus

$m = \frac{y - y_1}{x - x_1}$

$where (x_1,y_1) = (2,\frac{-1}{2})$

$So; x_1 = 2; y_1 = \frac{-1}{2}$

$m = 3$

By substituting the right values in the formula above;

$m = \frac{y - y_1}{x - x_1}$ becomes

$3 = \frac{y - \frac{-1}{2}}{x - 2}$

Multiply both sides by $(x - 2)$

$3 *(x - 2) = \frac{y - \frac{-1}{2}}{x - 2} *(x - 2)$

$3 *(x - 2) = (y - \frac{-1}{2})$

$3 *(x - 2) = (y + \frac{1}{2})$

$3(x - 2) = (y + \frac{1}{2})$

$3(x - 2) = y + \frac{1}{2}$

Reorder

$y + \frac{1}{2} = 3(x - 2)$

Hence, the equation that represents the line is $y + \frac{1}{2} = 3(x - 2)$

4 0

3 years ago