3a^2bx + 15cx^2y +25ad^3y

Mathematics

2 answers:

Svetach [21]3 years ago

7 0

Are you trying to factor? If so unfortunately you cannot factor this problem since there is no GCF that can be found.

marshall27 [118]3 years ago

4 0

The answer would remain the same.
Why: There are no like terms, the coefficients nor the exponents are alike.

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The figure below shows a straight line AB intersected by another straight line t:

BaLLatris [955]

When two straight lines intersect, the pairs of nonadjacent angles in opposite posi-tions are known as vertical angles.

If a segment AB is intersected by a transversal labeled t, then ∠1 and ∠3 and ∠2 and ∠4 are vertically angles formed by the transversal t on the segment AB.

Angles ∠1 and ∠2 can be described as adjacent and supplementary angles, so

$m\angle 1+m\angle 2=180^{\circ}$ .

Angles ∠3 and ∠2 can be also described as adjacent and supplementary angles, so

$m\angle 3+m\angle 2=180^{\circ}$ .

Subtract from the first equation the second equation:

$m\angle 1+m\angle 2-(m\angle 3+m\angle 2)=180^{\circ}-180^{\circ},\\ m\angle 1-m\angle 3=0,\\ m\angle 1=m\angle 3$ .

Similarly you can prove that $m\angle 2=m\angle 4$ .