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RUDIKE [14]
3 years ago
5

Ed decides to include more fruit in his diet he go to the grocery store over the weekend and buy six apples six oranges and six

avocados the total cost is $19.50 write an equation
Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
5 0

<u>Answer:</u>

x + y + z = 3.25

<u>Step-by-step explanation:</u>

We are given that Ed buys six apples, six oranges and six avocados and their total cost is $19.50.

We are to write an equation representing this.

Assuming apples to be x, oranges to be y and avocados to be z, we can write it as:

6 x + 6 y + 6 z = 1 9 . 5 0

Simplifying it by taking the common out to get:

x+y+z=3.25

tankabanditka [31]3 years ago
4 0

A=apple o=orange a=avocado

6A+6o+6a=19.50

Happy To Help! :D

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Ellie wants double her savings of £9000 by investing her money for 18 years what interest rate does she need to look for?
Genrish500 [490]
Answer is 20 % im not sure
5 0
3 years ago
A) Rate (R)<br>24/5<br>Time = 1 month<br>Interest = Rs. 39.96​
yKpoI14uk [10]

Answer:  P = $ 1,998.01

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 24%/100 = 0.24 per year,

putting time into years for simplicity,

1 months ÷ 12 months/year = 0.083333 years,

then, solving our equation

P = 39.96 / ( 0.24 × 0.083333 ) = 1998.007992032

P = $ 1,998.01

The principal required to

accumulate interest of $ 39.96

on a rate of 24% per year for 0.083333 years (1 months) is $ 1,998.01.

5 0
3 years ago
) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0
4 years ago
Consider the following system of equations. x + y = 11 2x - 3y = -3 Which equation can be added to the system so the solution do
3241004551 [841]

Answer:

Step-by-step explanation:

We have to find the system in which we can use the x and y from the given system of equations and make it hold true

From the given equations:

x+y = 11\\2x - 3y = -3

multiply top equation by -2 and add them

-2x - 2y = -22\\2x - 3y = -3\\-5y = -25\\y = 5\\x + 5 = 11\\x = 6

so, x = 6, y = 5

A: x-y = 2

6 - 5 = 1, so its not a

B: -2x + 2y = -2

-2(6) + 2(5) = -12 + 10 = -2

B works

just looking at C and D I can tell it doesnt work

So the answer is B

3 0
3 years ago
Which is the most accurate description of the polygon?
kherson [118]
Let’s take a look at the definitions of all of these categories of polygon:

A rhombus is a quadrilateral with four equal-length sides

A trapezoid is a quadrilateral with at least one pair of parallel sides

A kite is a quadrilateral with two pairs of equal sides, where those sides are adjacent to each other

A quadrilateral is a four-sided polygon

And let’s compare our definitions with the figure:

- None of the sides of the figure are equal to each other, so we it can’t be a rhombus
- The slopes of all of the sides are different, so the figure can’t have a pair of parallel lines, ruling out the chance that it’s a trapezoid
- That first bullet point also rules out the possibility that our figure is a kite
- Our figure *is* a four-sided polygon though, so it meets the requirements for a quadrilateral

So, the only label that works for this figure is a *quadrilateral*.
8 0
4 years ago
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