Answer: P = $ 1,998.01
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 24%/100 = 0.24 per year,
putting time into years for simplicity,
1 months ÷ 12 months/year = 0.083333 years,
then, solving our equation
P = 39.96 / ( 0.24 × 0.083333 ) = 1998.007992032
P = $ 1,998.01
The principal required to
accumulate interest of $ 39.96
on a rate of 24% per year for 0.083333 years (1 months) is $ 1,998.01.
Answer: 0.4512
Step-by-step explanation:
A bit string is sequence of bits (it only contains 0 and 1).
We assume that the 0 and 1 area equally likely to any place.
i.e. P(0)= P(1)= 
The length of bits : n = 10
Let X = Number of getting ones.
Then , 
Binomial distribution formula :
, where p= probability of getting success in each event and q= probability of getting failure in each event.
Here , 
Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.






Hence, the probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.
Answer:
Step-by-step explanation:
We have to find the system in which we can use the x and y from the given system of equations and make it hold true
From the given equations:

multiply top equation by -2 and add them

so, x = 6, y = 5
A: x-y = 2
6 - 5 = 1, so its not a
B: -2x + 2y = -2
-2(6) + 2(5) = -12 + 10 = -2
B works
just looking at C and D I can tell it doesnt work
So the answer is B
Let’s take a look at the definitions of all of these categories of polygon:
A rhombus is a quadrilateral with four equal-length sides
A trapezoid is a quadrilateral with at least one pair of parallel sides
A kite is a quadrilateral with two pairs of equal sides, where those sides are adjacent to each other
A quadrilateral is a four-sided polygon
And let’s compare our definitions with the figure:
- None of the sides of the figure are equal to each other, so we it can’t be a rhombus
- The slopes of all of the sides are different, so the figure can’t have a pair of parallel lines, ruling out the chance that it’s a trapezoid
- That first bullet point also rules out the possibility that our figure is a kite
- Our figure *is* a four-sided polygon though, so it meets the requirements for a quadrilateral
So, the only label that works for this figure is a *quadrilateral*.