3y(2y+5) solve the problem
1 answer:
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this is how I solve it
Given a quadratic equation 
1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.
In our case the coefficient of x is 10, so we write 10 as 2*5
2. then we write +
and - to the expression:
Answer:
1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.
In our case the coefficient of x is 10, so we write 10 as 2*5
2. then we write +
Answer: