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ch4aika [34]
3 years ago
11

GEOMETRY. image attached

Mathematics
1 answer:
Inessa [10]3 years ago
3 0
\bf \measuredangle DFC=\cfrac{1}{2}(\widehat{BG}+\widehat{CD})\implies 
\measuredangle DFC=\cfrac{\widehat{BG}+\widehat{CD}}{2}

you know what the arcCD is, and what the angle DFC is, so
solve for the arcBG
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20 pts awarded and brainliest chosen!!!!
g100num [7]

Answer:

D.  x <= -3 or   x >= 5

Step-by-step explanation:

3 | x-1 | > = 12

3(x - 1) >= 12

3x - 3 >= 12

3x >= 15

 x >= 5

or

-3(x - 1) >=  12

-3x + 3 >= 12

-3x >= 9

  x <= -3

Answer

x <= -3 or   x >= 5

4 0
3 years ago
Find exact values for sin θ and cos θ if tan θ = -√3 and θ terminates in Quadrant II.
vivado [14]
Hello : 
<span>tan θ = -√3
sin</span>θ = √3/2    1/2                      
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3 years ago
9a + 8 - 20-3-50<br> Answer
dem82 [27]

Answer:

9a-65

Step-by-step explanation:

simply write 9a+(add the remaining numbers all together)

5 0
3 years ago
Newton’s law of cooling states that the temperature of an object changes at a rate proportionalto the difference between the tem
Verizon [17]

Answer:

\frac{dT}{dt} = -0.05\;min^{-1}  (T-70\ºF)

Step-by-step explanation:

Hi!

Lets call:

T = temprature of the object

T₀ = temperature of surroundings

t = time

The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

\frac{dT}{dt} = -k(T-T_0) \\

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

\frac{dT}{dt} = -0.05\;min^{-1}  (T-70\ºF)

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