3 years ago

GEOMETRY. image attached

1 answer:

3 0

$\bf \measuredangle DFC=\cfrac{1}{2}(\widehat{BG}+\widehat{CD})\implies 
\measuredangle DFC=\cfrac{\widehat{BG}+\widehat{CD}}{2}$

you know what the arcCD is, and what the angle DFC is, so
solve for the arcBG

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g100num [7]

Answer:

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Step-by-step explanation:

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Answer

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Hello :
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Answer:

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Step-by-step explanation:

Hi!

Lets call:

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