All categories

2 years ago

I need help, lmk if you can do them..

Mathematics

2 answers:

OLEGan [10]2 years ago

7 0

Answer:

25) cos X = 12/37 cos X = 0.3243 X = 71.08 degrees

26) tan C = 32/24 tan C = 1.3333 C = 53.13 degrees

27) sin Z = 15/25 sin Z = 0.6 Z = 36.87 degrees

28) sin A = 32/40 sin A = 0.8 A = 53.13 degrees

29) sin Z = 40/50 sin Z = 0.8 Z = 53.13 degrees

Degger [83]2 years ago

4 0

Answer:

25) 0.3243

26) 1.3333

27) 0.6000

28) 0.8000

29) 0.8000

Step-by-step explanation:

sin = opp/hyp

cos = adj/hyp

tan = opp/adj

25) cos X = 12/37 = 0.324324324

26) tan C = 32/24 = 1.33333333

27) sin Z = 15/25 = 0.6

28) sin A = 32/40 = 0.8

29) sin Z = 40/50 = 0.8

You might be interested in

MARKING AS BRAINLIEST! LAST ATTEMPT! ) show ur work

Dvinal [7]

Answer:

√x³=√(x²·x)=x√x

√xy³z=√(x·y²·y·z)=y√xyz

√18x²y=√(3²·2·x²·y)=3x√2y

√32x⁴y²=√(2⁴·2·x⁴·y²)=2²x²y√2=4x²y√2

2√16x⁷y³z⁴=2√(2⁴·x⁶·x·y²·y·z⁴)=2³x³yz²√xy=8x³yz²√xy

-3√180x⁵y=-3√(3²·2²·5·x⁴·x·y)=-3(3)(2)x²√5xy=-18x²√5xy

5√108xyz²=5√(2²·3²·3·x·y·z²)=5(2)(3)z√3xy=30z√3xy

3x√xy¹⁰z⁷=3x√x·y¹⁰·z⁶·z)=3xy⁵z³√xz

x²√x³y²=x²√(x²·x·y²)=x²·x·y√x=x³y√x

3 0

2 years ago

spade realty sold lots for $23240 per hectare . what is total sales values if the lots in hectare were 2,3,4 ?

MArishka [77]

Answer:

2: $23,240
3: $23,240
4: $23,240

Step-by-step explanation:

You want to know the total sales value of 2, 3, or 4 lots per hectare, when each lot is sold for $23,240 per hectare.

<h3>Sales value</h3>

If lots are sold a the rate of $23,240 per hectare, it does not matter how many lots a hectare is divided into. Each hectare will have a total value of $23,240, regardless of the number of lots.

For example, if the hectare is divided into 10 lots, each will sell for ...

$23,240/10 = $2324.

The total value of those 10 lots is ...

10 × $2324 = $23,240.

Replacing 10 by N gives the same result:

N × ($23,240/N) = $23,240

Total sales values are $23,240 for any number of lots.

6 0

9 months ago

Use trigonometric substitution to evaluate the integral 13 + 12x − x2 dx . First, write the expression under the radical in an a

SCORPION-xisa [38]

I don't see a square root sign anywhere, so I'll assume the integral is

$\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx$

First complete the square:

$13+12x-x^2=49-(6-x)^2=7^2-(6-x)^2$

Now in the integral, substitute

$6-x=7\sin t\implies\mathrm dx=-7\cos t\,\mathrm dt$

so that

$t=\sin^{-1}\left(\dfrac{6-x}7\right)$

Under this change of variables, we have

$7^2-(6-x)^2=7^2-7^2\sin^2t=7^2(1-\sin^2t)=7^2\cos^2t$

so that

$\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx=-7\int\sqrt{7^2\cos^2t}\,\cos t\,\mathrm dt=-49\int|\cos t|\cos t\,\mathrm dt$

Under the right conditions, namely that cos(<em>t</em>) > 0, we can further reduce the integrand to

$|\cos t|\cos t=\cos^2t=\dfrac{1+\cos(2t)}2$

$\displaystyle-49\int|\cos t|\cos t\,\mathrm dt=-\frac{49}2\int(1+\cos(2t))\,\mathrm dt=-\frac{49}2\left(t+\frac12\sin(2t)\right)+C$

Expand the sine term as

$\dfrac12\sin(2t)}=\sin t\cos t$

Then

$t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \sin t=\dfrac{6-x}7$

$t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \cos t=\sqrt{7^2-(6-x)^2}=\sqrt{13+12x-x^2}$

So the integral is

$\displaystyle-\frac{49}2\left(\sin^{-1}\left(\dfrac{6-x}7\right)+\dfrac{6-x}7\sqrt{13+12x-x^2}\right)+C$

3 0

3 years ago

At a fixed operating setting, the pressure in a line downstream of a reciprocating compressor has a mean value of 950 kPa with a

prisoha [69]

Answer:

4.75% probability that the line pressure will exceed 1000 kPa during any measurement

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 950, \sigma = 30$