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3 years ago

Is -101 any rational or irrational number

Mathematics

2 answers:

Mashcka [7]3 years ago

8 0

Answer:

It is rational

Step-by-step explanation:

Step 1: Determine

A number is irrational if it does not terminate.

A number is rational if the number does terminate.

-101 terminates

Answer: It is rational

icang [17]3 years ago

4 0

Answer:

its a rational number

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Pls help!! need ur help math geniuses help with my last question! ty

Shtirlitz [24]

The expected value of the discrete distribution is of 20.97, hence option C gives the correct answer.

<h3>What is the mean of a discrete distribution?</h3>

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

Hence, according to the table, the expected value is given by:

E(X) = 12 x 0.08 + 18 x 0.15 + 20 x 0.31 + 22 x 0.08 + 24 x 0.15 + 25 x 0.23 = 20.97.

More can be learned about the expected value of a discrete distribution at brainly.com/question/26660401

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2 years ago

What number line is n > -2

Tresset [83]

Answer:

Step-by-step explanation:

Draw a straight line and put a point at the top of -2, then mark all numbers that are greater than -2 with black pen/pencil.

3 0

3 years ago

Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient.

NISA [10]

Answer:

Here we need to solve:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} }$

The sum of the fractions is equal to the quotient between the fractions.

Notice that the two values:

y = 3

y = -3

make the denominator equal to zero, so those values are restricted.

We can simplify the right side to get:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)} = 3*\frac{y + 3}{y - 3}$

Now we can multiply both sides by (y - 3)

$(y - 3)*(\frac{2}{y - 3} + \frac{6}{y + 3 }) = 3*(y + 3)\\2 + 6*\frac{y -3}{y + 3} = 3*(y + 3)$

Now we can multiply both sides by (y + 3)

$(2 + 6*\frac{y -3}{y + 3})*(y + 3) = 3*(y + 3)*(y + 3)$

$2*(y + 3) + 6*(y - 3) = 3*(y + 3)*(y + 3)\\\\2*y + 6 + 6*y - 18 = 3*(y^2 + 2*y*3 + 9)\\\\8*y - 12 = 3*y^2 + 6*y + 33\\\\0 = 3*y^2 + 6*y + 33 - 8*y + 12\\\\0 = 3*y^2 - 2*y + 45$

First, let's see the determinant of that quadratic equation:

$D = (-2)^2 - 4*3*45 = -536$

We can see that it is negative, thus, there are no real solutions of the equation.

Thus, there is no value of y such that the origina equation is true,

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3 years ago

PLEASE I NEED THIS ANSWER ASAP IF YOU ANSWER I WILL PUT YOU A BRAINLEST

Rudiy27

Answer:

choice b maybe?

Step-by-step explanation:

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3 years ago