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Vlada [557]
3 years ago
12

What is the lower quartile of the data? 16, 18, 59, 75, 30, 34, 25, 49, 27, 16, 21, 58, 71, 19, 50

Mathematics
1 answer:
svetlana [45]3 years ago
4 0

Answer:

19.

Step-by-step explanation:

First arrange in ascending order:

16, 16, 18, 19, 21, 25, 27, 30, 34, 49, 50, 58, 59, 71, 75.

There are a total of 15 numbers, so the median is the 8th number = 30.

The lower quartile is halfway alone the first 7 numbers which is the 4th number and it is 19.

The median which is the middle number

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Rina8888 [55]

Answer:

Step-by-step explanation:

OK you should really have these by now.

Translation, reflection and rotations do not change segment lengths or angular relationships. They only change line slopes and/or y-intercepts.

4 0
2 years ago
The dimensions of a rectangle is the length is 7in more than the width. If the length is double and the width is decreased by 3
polet [3.4K]

Answer: 4

Step-by-step explanation:

6 0
3 years ago
Evaluate the triple integral.
Irina-Kira [14]

The definition of the set E gives you a natural choice for the limits in the integral:

\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x \int_{x-y}^{x+y} y \, dz \, dy \, dx

Computing the integral, we get

\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x y ((x+y)-(x-y)) \, dy \, dx = 2 \int_0^6 \int_0^x y^2 \, dy \, dx

\displaystyle \iiint_E y \, dV = 2 \int_0^6 \frac13 (x^3 - 0^3) \, dx = \frac23 \int_0^6 x^3 \, dx

\displaystyle \iiint_E y \, dV = \frac23 \cdot \frac14 (6^4 - 0^4) = \boxed{216}

6 0
2 years ago
What number set does -3.8 belong in
Lerok [7]

Answer:

real number and rational number

Step-by-step explanation:

I infer that by number set you mean what kind of number it is. It is real because it is -3.8 and rational because it is terminating. It is not a integer, whole number, or natural number because -3.8 is a decimal

8 0
3 years ago
Can anyone help? <br><br>Give the answer in four significant figures.
Llana [10]
X + 0.5y = 3
x^2 - y = 15

from the first equation:-
0.5y = 3 - x
y = 6 - 2x

Substitute for y in second equation:-
x^2 - (6 - 2x) = 15
x^2 + 2x - 21 = 0
x  =  [-2 +/- sqrt((4 - 4*-21)] / 2
    = 3.6904 ,  -5.6904

Plugging in these into  first equation we get

3.6904 + 0.5y = 3  so y = 2(3-3.6904) =  -1.3808
-5.6904 + 0.5y = 3 so y = 2(3 + 5.6904) =  17.3808

Solution is  x = 3.690, y = -1.381  ;   x = -5.690, y = 17.38 ( to 4 s.f's)

5 0
3 years ago
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