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Morgarella [4.7K]
4 years ago
15

There are two newborns, Gary and Eric. The future lifetime of Gary is uniformly distributed between 0 to 60 years. The future li

fetime of Eric is uniformly distributed between 0 to 40 years. Their future lifetimes are independent. Calculate the probability that Gary dies first
Mathematics
1 answer:
scoray [572]4 years ago
3 0

Answer:

\text{The probability that Gary dies first = }\frac{1}{3}

Step-by-step explanation:

To find the required probability,

We can split the 40 years of Eric into very small pieces of time dt. Now, If Eric dies at time t and Gary dies before Eric, the probability is :

\frac{t}{60}\times \frac{dt}{40}=\frac{t\cdot dt}{2400}

Hence the probability that Gary dies first is  given by :

=\int_{0}^{40}\frac{t}{2400}dt \\\\= \frac{1}{3}

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You have a lot of questions here, try breaking them up into multiple posts and you may get more responses.

I will help with some.

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The solution is just -3.
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The two solutions are 0 and 4.
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3 0
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