Let the length of side AB be $x$, then
Therefore, the perimeter of ABCDE is 2(12) + 2(4) + 6 = 24 + 8 + 6 = 38 in.
Twice a number is more than the sum of that number and 14.
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Let the length of side AB be $x$, then
Therefore, the perimeter of ABCDE is 2(12) + 2(4) + 6 = 24 + 8 + 6 = 38 in.