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3 years ago

How do I ace a test that I am not prepared for?

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

4 0

You either start studying now or you fake it and guess and get lucky or you cheat

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A skirt costs $20 more than the blouse. the skirt costs $65. what is the price of the blouse. write an equation. then solve the

Aleksandr [31]

$65 - $20
=$45

$65=the skirt

$45=the blouse

8 0

3 years ago

Which of the following statements are correct based on the diagram? Select all that apply.

cluponka [151]

Answer:

Segment U T is congruent to segment X V

Segment S T is congruent to segment W V

Angle V is congruent to angle T

7 0

2 years ago

If you have 20 dollars and you you need to give your friend 5 dollars out of that, how much money will you have left

notsponge [240]

Answer: 15 dollars
20 -5 = 15

4 0

3 years ago

Find the equation of the line parallel to y=2x+1 that contains point (14,3)

Sophie [7]

First of all, remember what the equation of a line is:

$y=mx+b$

Where:

m=slope

b=y-intercept.

Given this information, we can start by plugging in what we know, we are given the slope which is 2 so we can fill that in, remember m=slope

$y=2x+b$

To find b, think about what your (x,y) point means:(14,3). When x of the line is 14, y of the line must be 3.

Because we were given the point (14,3)

We need to find the value of b. The 2 is already set and x and y are variables. We want the equation for the line that specifically passes through the given point (14,3).

Plug in for x the number 14 and for y the number 3:
(14,3).
y=mx+b or 3=2 × 14+b,

solving for b: b=3-(2)(14). b=-25.

Plug that in for b:
y=2x-25
Final answer:
y=2x-25

8 0

3 years ago

The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th

Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

$A=\frac{1}{2} (b_{1} +b_{2} )h$

where, h be the height of the trapezoid

$b_{1}$ be the shorter base

$b_{2}$ be the longer base

As per the given problem,

$b_{2}=b_{1} +6$

Now,

Putting, A=72, $b_{2}=b_{1}+6$ and h=6 we get,

$\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72$

or, $b_{1}+b_{1}+6 = \frac{(72)(2)}{6}$

or, $2b_{1}+6 = 24$

or, $2b_{1}=24-6$

or, $b_{1}= \frac{18}{2}$

or, $b_{1}=9$

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

5 0

3 years ago