$\bf \textit{area of a triangle}=A=\cfrac{1}{2}bh\qquad 
\begin{cases}
b=base\\
h=\textit{height or altitude}
\end{cases}\\\\
-----------------------------\\\\
\textit{area of a trapezoid}\\\\
A=\cfrac{h}{2}(a+b)\qquad 
\begin{cases}
a=\textit{base, or one of the parallel sides}\\
b=\textit{base, or the other parallel side}\\
h=\textit{height, the distance between both}\\
\qquad \textit{parallel sides}
\end{cases}$

7 0

3 years ago

Maya earns 72 dollars for working 5 hours. How long will it take for her to earn 216 dollars at the same pay rate?

hjlf

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Determine the area of the composite figure.

MaRussiya [10]

Answer:

$110\ in^2$

Step-by-step explanation:

$1)\ A_1 = b * h_1 = 10 * 8 = 80\ in^2$

$2)\ A_2 = \frac{b*h_2}{2} = \frac{10*(14-8)}{2} = \frac{10*6}{2} = \frac{60}{2} = 30\ in^2$

$3)\ A = A_1 + A_2 = 80 + 30\ in^2 = 110\ in^2$

6 0

2 years ago

write the standard equation for the circle with the center at (4,1) and passing through the point (0,1)

Airida [17]

Without needing the distance formula

from 4,1 to 0,1, you move the "x" from 4 to 0, over the same "y" value of 1, so is just 4 units long, from the center to an endpoint, and the chord that stems from the center to an endpoint is the radius, so r = 4

$\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&4&1&4
\end{array}$

3 0

3 years ago