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3 years ago

A carton contains soup cans weighing a total of 20 pounds. Each can weighs 1 1/4 pounds. How many cans does the carton contain?

2 answers:

6 0

First I would convert the fraction to a mixed number, 7 9/13, 6 1/3, etc. 11/4 rewritten as a mixed number is 2 3/4 because 4 goes into 11 twice (if you need more help with mixed numbers get help from your teacher or look online)! Now we need to find out how many times 2 3/4 lbs. (1 soup can) goes into 20 pounds. I would convert the original fraction 11/4 into a decimal by dividing 11 by 4. Then it would be 20 lbs (carton) divided by 2.75 lbs. (can).
See if you can get the final answer using the equation: $20/2.75 = x$

Morgarella [4.7K]3 years ago

5 0

I believe there would be 16 cans

do 20 divide 5/4 (=1 1/4)

so 20 * 4/5 which would be 80/5; simplifies to 16 cans

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Step-by-step explanation:

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3x = - 5 - 22

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x = -27 / 3

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Solve the system. Enter the smallest x-coordinate first

pentagon [3]

$y= 3 \,\,,\,\,x= -2 \,\,and\,\, y=3\,\,,\,\, x=2$

Step-by-step explanation:

Solving the following system of equations:

$x^2-y=1\\2x^2+y^2=17$

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$x^2-y=1\,\,\,(1)\\2x^2+y^2=17\,\,\,(2)$

Putting value of x^2 in eq(2)

$x^2 = 1+y\\Putting\,\,value\,\,of\,\,x^2\,\,in\,\,eq(2)\\2(1+y)+y^2=17\\2+2y+y^2=17\\y^2+2y+2-17=0\\y^2+2y-15=0\\Factorizing:\\y^2-3y+5y-15=0\\y(y-3)+5(y-3)=0\\(y+5)(y-3)=0\\y+5=0 \,\,and \,\, y-3=0\\y = -5 \,\,and \,\, y=3$

Now, finding value of x

Putting y=-5

$x^2 = 1+y\\x^2=1-5\\x^2=-4\\Taking\,\,square\,\,root\\x= \pm2i$

y=-5, x= 2i and y=-5 , x= -2i

Since we need to find x and y coordinates and its value cannot be in terms of i so we will not consider these as answer

Putting y=3

$x^2 = 1+y\\x^2=1+3\\x^2=4\\Taking\,\,square\,\,root\\x= \pm2$

So, $y= 3 \,\,,\,\,x= -2 \,\,and\,\, y=3\,\,,\,\, x=2$

Keywords: system of equations

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