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motikmotik
3 years ago
8

Can someone please help me with these three questions?!! The subject is Algebra 2.

Mathematics
1 answer:
Burka [1]3 years ago
8 0
On January 1,1980 a city had 100,000 people.during the year 1,000 people died,2,000 babies were born 3,000 people moved out ,and 10,000 moved in.how many people were in the city by the end of 1980?
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40% of the memberships sold by Gym A were gold memberships.
Aneli [31]

Answer:

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

Step-by-step explanation:

Here is the complete question: 40% of the memberships sold by Gym A were gold memberships. 25% of the memberships sold by Gym B were gold memberships.  

Which statement must be true?

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

b) If both gyms sold the same number of memberships, Gym A sold 15 more gold membership.

c) Gym A sold more gold membership than Gym A did.

d) If Gym B sold 50 membership, 25 would be gold memberships.

Given: Gym A have sold 40% gold membership of total membership.

Gym B have sold 25% gold membership of total membership.

Lets take option A first to find if it is true statement.

As per option A, There are total number of membership is 80.

∵ Gym A has sold 40% gold membership.

∴ Gym A gold membership= 40\% \times 80

⇒ Gym A gold membership= \frac{40}{100} \times 80= 32 member.

∴ Gym A gold membership= 32.

Now, Gym B

∵ Gym B has sold 25% gold membership.

∴ Gym B gold membership= 25\% \times 80

⇒ Gym B gold membership= \frac{25}{100} \times 80=20 member.

∴ Gym B gold membership= 20.

Next finding difference gold membership for Gym A and Gym B

32-20= 12 \ membership

Hence, we can say option A is correct as Gym A have sold 12 more gold membership, if total number of membership sold by both Gym is 80.

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