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alexdok [17]
3 years ago
12

Help please!!!!!... my teacher is being mad annoying and telling me to redo

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
7 0

Question 1) quadratic function

This is not to be confused with the quadratic formula, which is of a similar name. A quadratic function is something like y = 5x^2+10x+17.

============================================================

Question 2) Factoring method

This is where we take something like x^2+5x+6 = 0 and turn it into (x+3)(x+2) = 0, then use the zero product property getting x+3 = 0 or x+2 = 0. This leads to x = -3 or x = -2

============================================================

Question 3) Quadratic formula

This is the fairly messy/complicated formula as shown below. It's something to either write down on a reference card or just memorize.

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

Luden [163]3 years ago
5 0

Answer:

Question 1) quadratic function

This is not to be confused with the quadratic formula, which is of a similar name. A quadratic function is something like y = 5x^2+10x+17.

============================================================

Question 2) Factoring method

This is where we take something like x^2+5x+6 = 0 and turn it into (x+3)(x+2) = 0, then use the zero product property getting x+3 = 0 or x+2 = 0. This leads to x = -3 or x = -2

============================================================

Question 3) Quadratic formula

This is the fairly messy/complicated formula as shown below. It's something to either write down on a reference card or just memorize.

Step-by-step explanation:

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Find the greatest possible error for the measurement 0.991 g.
Veronika [31]
Explanation:

Any calibration scale consists of markings indicating calibrated values. The ‘space’ between the marks (lines) is the area of uncertainty with respect to the calibration.

Thus, the possible error is always one-half of the value between the markings, because ON either one you have a calibrated value. In between, no matter how close you think you can “judge” the distance, there is no calibrated reference point, so the ‘error’ of stating a value is +/- the value of half of the calibration accuracy. 0.991 is accurate (assuming that is the calibration limit), and 0.992 or 0.990 would also be “accurate”. The possible error is the +/- 0.0005 beyond that third digit that might be more to one side or the other.

That means the measured value of 0.991g could be between 0.9905g and 0.9915g.

4 0
3 years ago
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Y=-3x+3/4 what is the slope and y intercept
Len [333]

Answer:

the slope is equal to m or in this case 3. the y intercept is equal to b or 3/4

Step-by-step explanation:

8 0
3 years ago
Fon baked a cake and ate 1/8 of it she shared the remaining cake equally to her 4 friends whag Frection of the whole cake did ea
jok3333 [9.3K]

Answer:

Each of her friends ate 7/32 of the cake.

Step-by-step explanation:

Given that Fon baked a cake and ate 1/8 of it, and then she shared the remaining cake equally to her 4 friends, to determine what fraction of the whole cake did each of her friends received, the following calculation must be performed:

(8 - 1/8) / 4 = X

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(28/32) / 4 = X

7/32 = X

Thus, each of her friends ate 7/32 of the cake.

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3 years ago
Simplify,<br> Rewrite the expression in the form 2n.<br> 2.2.2.2.2.2.2.2<br> 2.2.2.2
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Before answering this question let us know what are net and total areas.

\text{Net area}= \text{total area above x-axis}-\text{total area below x-axis}

\text{Total area}= |\text{total area above x-axis}|+|\text{total area below x-axis}|

Now let us look at first part of our question. Net area of our region will be equal to total area of region when the whole region lies above x axis because then our whole region is positive.

The net area of a region will differ from the total area of the region when some part of our region is above x-axis and some part of region is below x-axis. This is because we have to subtract area of region which is below x-axis from area above x-axis to get net area.

7 0
3 years ago
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