Help please!!!!!... my teacher is being mad annoying and telling me to redo

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

7 0

Question 1) quadratic function

This is not to be confused with the quadratic formula, which is of a similar name. A quadratic function is something like y = 5x^2+10x+17.

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Question 2) Factoring method

This is where we take something like x^2+5x+6 = 0 and turn it into (x+3)(x+2) = 0, then use the zero product property getting x+3 = 0 or x+2 = 0. This leads to x = -3 or x = -2

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Question 3) Quadratic formula

This is the fairly messy/complicated formula as shown below. It's something to either write down on a reference card or just memorize.

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Luden [163]3 years ago

5 0

Answer:

Question 1) quadratic function

This is not to be confused with the quadratic formula, which is of a similar name. A quadratic function is something like y = 5x^2+10x+17.

============================================================

Question 2) Factoring method

This is where we take something like x^2+5x+6 = 0 and turn it into (x+3)(x+2) = 0, then use the zero product property getting x+3 = 0 or x+2 = 0. This leads to x = -3 or x = -2

============================================================

Question 3) Quadratic formula

This is the fairly messy/complicated formula as shown below. It's something to either write down on a reference card or just memorize.

Step-by-step explanation:

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Is 400 pints greater than less than or equal to 100 gallons

adell [148]

400 Imperial pints are less than 100 Imperial gallons,
400 pints = 50 gallons.

6 0

3 years ago

40 points” help HLP HL

cestrela7 [59]

Answer:

D: {(-5, -4, 2, 2, 5)}

R: {(-6, 3, 4, 1, 5)}

The relation is NOT a function.

Step-by-step explanation:

By definition:

A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a <em><u>relation</u></em> in which no two ordered pairs have the same first component (domain/input/x value) and different second components (range/output/y value).

Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).

Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.