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Rina8888 [55]
4 years ago
7

Can Anybody Answer This For Me ?

Computers and Technology
1 answer:
AlladinOne [14]4 years ago
3 0

Answer:

I'm pretty sure its 3 only (c) III only gimme brainliest

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Write a program that accepts a number as input, and prints just the decimal portion.
Olegator [25]

<u>Answer:</u>

<em>There are 2 ways to do extract the decimal part: </em>

<u>Explanation:</u>

  • <em>First method using number  </em>

<em>int main() { </em>

<em>  double num = 23.345; </em>

<em>  int intpart = (int)num; </em>

<em>  double decpart = num - intpart; </em>

<em>  printf(""Num = %f, intpart = %d, decpart = %f\n"", num, intpart, decpart); </em>

<em>} </em>

  • <em>Second method using string: </em>

<em>#include <stdlib.h> </em>

<em>int main() </em>

<em>{ </em>

<em>    char* inStr = ""123.4567"";          </em>

<em>    char* endptr;                       </em>

<em>    char* loc = strchr(inStr, '.'); </em>

<em>    long mantissa = strtod(loc+1, endptr); </em>

<em>    long whole = strtod(inStr, endptr);  </em>

<em>    printf(""whole: %d \n"", whole);      </em>

<em>    printf(""mantissa: %d"", mantissa);   </em>

<em>} </em>

8 0
3 years ago
Read 2 more answers
Java provides a number of interfaces and classes to systematically implement collections.
solmaris [256]

Answer:

A) True

Explanation:

Java provides collections architecture or framework used to store and manipulate a group of objects or collections.

The collection framework has interfaces which include; Set, Queue, Deque, List, as well as classes which include; Hashset, ArrayList, LinkedList, LinkedHashset, PriorityQueue, Vector and TreeSet.

There are also many methods declared in the collection interface which include; add(), addAll(), remove(), removeAll(),retainAll(), clear(), size(), iterator(), toArray() etc

4 0
4 years ago
"Write an iterative function iterPower(base, exp) that calculates the exponential baseexp by simply using successive multiplicat
sp2606 [1]

Answer:

I am writing the function using Python. Let me know if you want the program in some other programming language.            

def iterPower(base, exp):    

    baseexp = 1

    while exp > 0:

        baseexp = baseexp*base

        exp= exp - 1

    return baseexp

base = 3

exp = 2

print(iterPower(base, exp))

Explanation:

  • The function name is iterPower which takes two parameters base and exp. base variable here is the number which is being multiplied and this number is multiplied exponential times which is specified in exp variable.
  • baseexp is a variable that stores the result and then returns the result of successive multiplication.
  • while loop body keeps executing until the value of exp is greater than 0. So it will keep doing successive multiplication of the base, exp times until value of exp becomes 0.
  • The baseexp keeps storing the multiplication of the base and exp keeps decrements by 1 at each iteration until it becomes 0 which will break the loop and the result of successive multiplication stored in baseexp will be displayed in the output.
  • Here we gave the value of 3 to base and 2 to exp and then print(iterPower(base, exp)) statement calls the iterPower function which calculates the exponential of these given values.
  • Lets see how each iteration works:
  • 1st iteration

baseexp = 1

exp>0 True because exp=2 which is greater than 0

baseexp = baseexp*base

               = 1*3 = 3

So baseexp = 3

exp = exp - 1

      = 2 - 1 = 1    

exp = 1

  • 2nd iteration

baseexp = 3

exp>0 True because exp=1 which is greater than 0

baseexp = baseexp*base

               = 3*3 = 9

So baseexp = 9

exp = exp - 1

      = 1-1 = 0    

exp = 0

  • Here the loop will break now when it reaches third iteration because value of exp is 0 and the loop condition evaluates to false now.
  • return baseexp statement will return the value stored in baseexp which is 9
  • So the output of the above program is 9.
5 0
3 years ago
8. Given the array String[] words, which already contains 1 or more values, write a block of code which counts and returns the n
Vikentia [17]

Answer:

Following are the code to this question:

public class Main//defining a class

{

public static void main(String[] arg)//defining main method

{

  String[] words={"Key","day", "Know", "kind"};//defining array of String words

  int x=0;//defining integer variable for count value

  for(int i=0;i<words.length;i++)//defining for loop for count value

  {

 if(words[i].startsWith("k")||words[i].startsWith("K"))//use if block to check word start from k

  x=x+1;//increment the value of x

  }

System.out.print("The number of letters which starts from k is: "+ x);//print value with message

}

}

Output:

The number of letters which starts from k is: 3

Explanation:

In this code, inside the main method an array of String "words" is defined that hold a value, and in the next step an integer variable "x" is defined, which is used to count the letters, which starts from k.

For this, a for loop is used that counts the value and in this an, if block is defined that uses the "startsWith" method to check the value and increment the value of x and at the last, it prints its value.

7 0
3 years ago
g You and your friend both send documents to the printer, but the printer can only print one document at a time. What does it do
Sedbober [7]

Answer:

It places the document in a buffer

Explanation:

Since the printer can only print a document at a time, the other document is going to be placed in a buffer.

The print buffer can be described as a location in memory that has the function of holding data that is going to be sent to a computers printer. A print job such as in this scenario may remain in the buffer because another document is to be printed first.

Sometimes a document could be put in the buffer because the computer is waiting for the printer to respond. This is just another reason why documents are placed in a buffer.

5 0
3 years ago
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