Answer:
Unicode
Explanation:
This is a fairly large code and Is well known throughout my family since we study ancient codex and modern codes to solve crimes and find relics of the past, although our research has proven good and unicode is one that is being studied currently now, I have found it as long and very time consuming. Although ASCII is a computer code that consists of graphs and numbers it actually shortens the text. and hexadecimal has been proven to be less reliable and binary is a short code with little symbols
// making the class
class Counter {
int counter;
int limit;
// Constructor
Counter(int a, int b){
counter = a;
limit = b;
}
// static function to increment
static increment(){
if(counter<limit)
nCounter+=1;
}
// Decrement function
void decrement(){
if(counter>0)
nCounter-=1;
}
int getValue(){
return counter;
}
static int nCounter;
int getNCounters(){
return nCounter;
}
};
// Initializa the static
int Counter::nCounter = 0;
I think the answer would be "superscript"
Answer:
#include <iostream>
using namespace std;
void PrintPopcornTime (int bagOunces){
if (bagOunces < 2){
cout << "Too small"<<endl;
}
else if (bagOunces > 10){
cout << "Too large"<<endl;
}
else{
cout << bagOunces*6 <<" seconds"<<endl;
}
}
int main(){
PrintPopcornTime(7);
return 0;
}
Explanation:
Create a function called PrintPopcornTime that takes one parameter, bagOunces
Check the bagOunces using if-else structure. If it is smaller than 2, print "Too small". If it is greater than 10, print "Too large". Otherwise, calculate and print 6*bagOunces followed by " seconds".
Call the function in the main function with parameter 7. Since 7 is not smaller than 2 or not greater than 10, "42 seconds" will be printed.
