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3 years ago

Find the area of this regular polygon.

Mathematics

1 answer:

AveGali [126]3 years ago

5 0

8.37 percent off the pointe of school tmw is a good day to go eat

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Margie has $100. She wants to buy a book for $20 and some CDs for $15 each. At most, how many CDs can Margie buy?

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Margie can buy 5 CDs at most.

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3 years ago

Which number is between 21 and 3 pie dived by 2

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12. 12 divided by 2 is 6

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3 years ago

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The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure

Novosadov [1.4K]

Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?

Use 3.14 to approximate π .

Enter your answer in the box. in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cylinder volume)

$V = \pi *r^2*h$

$V = 3.14 *2.5^2*7$

$V = 3.14*6.25*7$

$V = 137.375 \to \boxed{V_{cylinder} \approx 137.38\:in^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$

Formula: (Volume of the hemisphere)

$V = 2* \pi * \dfrac{r^3}{3}$

Solving:

$V = 2* \pi * \dfrac{r^3}{3}$

$V = 2*3.14 * \dfrac{2.5^3}{3}$

$V = 2*3.14 * \dfrac{15.625}{3}$

$V = \dfrac{98.125}{3}$

$\boxed{ V_{hemisphere} \approx 32.70\:in^3}$

Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)

Volume of the figure = cylinder volume + hemisphere volume

Volume of the figure = 137.38 in³ + 32.70 in³

$Volume\:of\:the\:figure =170.08 \to \boxed{\boxed{\boxed{Volume\:of\:the\:figure = 170\:in^3}}}\end{array}}\qquad\quad\checkmark$

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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3 years ago

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Jen knows that (-1, 41) and (5, 41) lie on a parabola defined by the equation y=4x^2-16x+21. How can I find the coordinates of t

andreyandreev [35.5K]

The vertex is at (2, 5).

To find the vertex, we first find the axis of symmetry; this is given by

x = -b/2a

For our equation, b = -16 and a = 4:
x = -(-16)/2(4) = 16/8 = 2

We substitute this back into our equation:
y = 4(2)² - 16(2) + 21 = 4(4) - 32 + 21 = 5

Therefore the vertex is at (2, 5).

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3 years ago

5/14 - - 1/14 I will provide a picture

m_a_m_a [10]

Answer:

$\frac{3}{7}$