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3 years ago

a radio when sold at a certain price gives 20%. what will be the gain percent if sold for thrice the price

Mathematics

2 answers:

-Dominant- [34]3 years ago

8 0

Answer: 200%
Your welcome

Dominik [7]3 years ago

7 0

Answer: 200%

Step-by-step explanation:

A radio when sold at a certain price gives a gain of 20 %.

Selling Price = 3 × Cost Price

TO FIND :- Gain percent

Gain % = gain / cp x 100

20 = (gain x 100) / cp

Gain/cp = 20/100 = 1/5

Gain = SP - CP

= 3CP - CP

Gain = 2CP

Gain% = gain / cp x 100

= 2cp / cp x 100

= 2 x 100 = 200%

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Determine whether or not f is a conservative vector field. if it is, find a function f such that f = ∇f. if it is not, enter non

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$f(x,y) = (y \ e^{x} + sin(y) \hat{i} + (e^{x}+x \, cosy) \hat{j}$

Note that if the field is of the form
$\vec{f} = P\hat{i} + Q\hat{j}$
then the condition for the field to be conservative is that
$\frac{\partial P}{\partial y} = \frac{\partial Q}{\partial x}$

For the given field,
$\frac{\partial P}{\partial y} =e^{x} + cos y \\ \frac{\partial Q}{\partial x} = e^{x}+cosy$

Because the condition is satisfied, the given field is conservative.
To find the function that satisfies
$f= \bigtriangledown f$

$f(x,y) = \int P(x,y)dx = ye^{x} + x\, siny + g(y)$
Because $\frac{\partial P}{\partial y} = \frac{\partial Q}{\partial x}$ , therefore
$\frac{\partial f}{\partial y} =e^{x} + x \, siny + g'(y)$
Because $\frac{\partial f}{\partial y} =Q = e^{x} + x \, cosy$
therefore
g'(y) = 0
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Answer:
(a) The given function is conservative.
(b) The function is
$f(x,y) = ye^{x} + x \, siny + c$
where c = constant.

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4 years ago

a radio when sold at a certain price gives 20%. what will be the gain percent if sold for thrice the price​

a radio when sold at a certain price gives 20%. what will be the gain percent if sold for thrice the price