The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Since 3in, 4in, and 8in. Since 6+14 > 10,6+ 10 > 14, and 10 + 14 > 6, you can form a triangle with the lengths 6m, 14m, and 10m.
For this problem, the most accurate is to use combinations
Because the order in which it was selected in the components does not matter to us, we use combinations
Then the combinations are 
n represents the amount of things you can choose and choose r from them
You need the probability that the 3 selected components at least one are defective.
That is the same as:
(1 - probability that no component of the selection is defective).
The probability that none of the 3 selected components are defective is:
Where 
is the number of ways to select 3 non-defective components from 117 non-defective components and 
is the number of ways to select 3 components from 120.
So:
Finally, the probability that at least one of the selected components is defective is:
P = 7.4%
Question 9 is A, and question 10 is 10^5.
Answer:
He gets $10 for his weekly allowance.
Step-by-step explanation:
Let x represent the amount that Fred gets for his allowance weekly.
Fred spent half his allowance on the movies. This means that the total amount that he spent on the movies is x/2. The amount that he is left with would be
x - x/2 = x/2
He washed the family car for six dollars. This means that the total amount that he is left with would be
x/2 + 6
if he now has eleven dollars, it means that
x/2 + 6 = 11
x/2 = 11 - 6 = 5
x = 2 × 5 = $10
