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telo118 [61]
3 years ago
6

fiona needs to choose a five-character passord with a combination of three letters and the even numbers 0,2,4,6,or 8 if she uses

her initial F,J,and S, in order as the first three characters and she does not use the same digit more than once in her passord how many different possible way are there
Mathematics
1 answer:
Wittaler [7]3 years ago
7 0
For the five characters of the five-character password, the first three slots are already taken for the initial F, J, S, the password would become,
                                         FJS_ _
The last two slots could be any of the even digits. In the fourth slot, Fiona can have any of the 5 values. On the fifth slot, she can have only 4 choices as the other digit was already used. Multiplying 5 and 4, the answer would be 20. 
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Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
Tems11 [23]

Answer:

0.75

Step-by-step explanation:

Given,

P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,

P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,

Where,

A = event that the selected student has a Visa card,  

B = event that the selected student has a MasterCard,  

C = event that the selected student has an American Express card,

We know that,

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07

= 0.75

Hence, the probability that the selected student has at least one of the three types of cards is 0.75.

5 0
3 years ago
What is the justification for each step in the solution of the equation?
Alexandra [31]

For this case we have the following equation:

\frac{2}{3}x-\frac{1}{3}= 2 (x + 2)\\

If we multiply both sides of the equation by 3 we get:

2x-1 = 6 (x + 2) ---> Multiplication Property of Equality

Applying the distributive property we have:

2x-1 = 6x + 12 ---> Distributive Property

Adding 1 on both sides of equality we have:

2x-1 + 1 = 6x + 12 + 1\\

2x = 6x + 13 ---> Addition Property of Equality

Subtracting 6x on both sides we have:

-6x + 2x = 6x-6x + 13\\

-4x = 13 ---> Subtraction Property of Equality

Finally, dividing by -4 on both sides we have:

\frac{-4x}{-4}= \frac{13}{-4}\\

x = -\frac{13}{4}---> Division Property of Equality


5 0
3 years ago
Read 2 more answers
This is geometry, I need help! Please and thanks!!
denis23 [38]

Problem 8

Answer: angle LSO and angle MSN

--------------

Explanation:

Vertical angles form when we intersect two line segments, lines, or rays. Vertical angles are opposite one another and they are always congruent.

=============================================

Problem 9

Answer: angle LMS and angle SMN

--------------

Explanation:

Adjacent angles share a common line, line segment, or ray. Think of two adjacent rooms sharing a common wall between them. In the case of the answer above, the two angles share the common segment SM (note how S and M are part of LMS and SMN)

When it comes to naming angles, the middle letter is always the vertex of the angle. This is the hinge so to speak. Or you could picture a pair of scissors. For angle LMS, the arms LM and SM are the two blades of the scissors while point M is where the blades meet.

=============================================

Problem 10

Answer: angle LSM and angle MSN

--------------

Explanation:

Same idea as problem 9. Now we're making S the middle letter. Something like angle LSM is the same as angle MSL.

In this case, the two adjacent angles form a straight line. We consider these two angles a linear pair.

=============================================

Problem 11

Answer: angle LSO and angle OSN

--------------

Explanation:

The term linear pair was discussed back in problem 10. So you could list those two angles again, or you could go with another pair as shown above. All that matters is that they are adjacent angles and they are supplementary angles (they add to 180 degrees). There are many possible answers.

Something like the angle pair angle LOS and angle NOS are adjacent angles, but they aren't supplementary. So we don't meet the condition of a linear pair here.

5 0
3 years ago
I need help please! this is on EDGE2020 !
Margaret [11]

Answer:

D

Step-by-step explanation

A. there are 6 triangles so not this

B. Only 2 rectangles

C. 6 triangles once again

D. everything matches

5 0
3 years ago
Read 2 more answers
A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is ce
Scilla [17]
Answer: Assuming the riders starts at the position (20, 0) on the x-axis, the exact position of the rider will be (20cos75, 20sin75) or about (5.18, 19.32).

The angle for 5pi/12 radians is 75 degrees. Therefore, to find the position we can use the sine and cosine of 75 to find the x and y value of the coordinate.

For the y-value, we can write and solve:
sin75 = x/20

For the x-value, we can write and solve:
cos75 = x/20
3 0
3 years ago
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