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Alexus [3.1K]
4 years ago
15

Suppose you have a litter of mice which consists of 8 males and 4 females. If you randomly grab two of them, what is the probabi

lity that they are both male? You may think of this questions as without replacement. Keep your answer in decimal form and round to THREE decimal places.
Mathematics
1 answer:
tiny-mole [99]4 years ago
5 0

Answer:

The probability that they are both male is 0.424 (3 d.p.)

Step-by-step explanation:

The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter

Prob (1st male) = 8 ÷ 12 = 0.667

Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.

Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636

Therefore,

Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424

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A) If a:b = 2:5 and b:c = 3:4, find (i) a:c(ii) a:b:c
kobusy [5.1K]

Answer:

A i. a:c=3:10

ii. a:b:c=2:5:10

B i. x:z=2:5

ii. x:y:z=2:4:5

Step-by-step explanation:

A.) If a:b = 2:5 and b:c = 3:4, find (i) a:c(ii) a:b:c

a:b=a/b=2/5

b:c=b/c=3/4

a/b*b/c=a/c

2/5*3/4=a/c

6/20=a/c

3/10=a/c

Therefore, a:c=3:10

a:b:c

a:b=2:5

b:c=3:4

b is common to both ratios

The value of b in the first ratio is 5 and b is 3 in the second ratio

Lets take the LCM of both values

LCM of 5 and 3=15

So, we will change the value of b in the first ratio and second ratio to 15

By doing this, we will multiply the whole first ratio by 3

We have, 6:15

We multiply the whole second ratio by 5

We have, 15:20

Therefore a:b:c=6:15:20

=2:5:10

B. If x:y = 1:2 and y:z = 4:5,

x:y=x/y=1:2

y:z=y/z=4:5

x/y*y/z=x/z

1/2*4/5=x/z

4/10=x/z

2/5=x/z

Therefore, x:z=2:5

x:y:z

x:y=1:2

y:z=4:5

y is common to both ratio

Take the LCM of y values in both ratio

LCM of 2 and 4 =4

So,we will change the value of y in the first and second ratio to 4

By doing this, we will multiply the whole first ratio by 2

We have, 2:4

We will also multiply the whole second ratio by 1

We have, 4:5

Therefore, x:y:z=2:4:5

8 0
3 years ago
Describe the graph of the function f(x) = x3 − 11x2 + 36x − 36. Include the y-intercept, x-intercepts, and the shape of the grap
Kamila [148]
For a polyonomial
P(x)=ax^n+bx^(n-1)...zx^0
when n is odd, the endpoints of the graph point in oposite directions
when n is even, the endpoints of the graph point in same direction

a is the leading term
when a is positive and:
1. n is odd, the graph goes from bottom left to top right
2. n is even, the graph goes from top left to top right

when a is negative and:
1. n is odd, the graph goes from top left to bottom right
2. n is even, the graph goes from bottom left to bottom right



xintercept is where the line crosses the x axis or when y=0
yintercept is where the line crosses the y axis or when x=0




f(x)=1x^3-11x^2+36x-36
leading term is positive and odd degree

graph goes from bottom left to top right, has 1 inflection point

yint, sub 0 for all x's
f(0)=0^3-11(0)^2+36(0)-36
yintercept is y=-36 or (0,-36)

xintercept
set function equal to zero
0=x^3-11x^2+36x-36
factor
0=(x-2)(x-3)(x-6)
x=2,3,6
xintercepts are at x=2,3,6 or (2,0), (3,0) and (6,0)
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