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Shalnov [3]
3 years ago
10

Please need help thank you

Mathematics
2 answers:
myrzilka [38]3 years ago
7 0

Answer:translate 5 down reflect over y axis. Same steps different order if you start with (1,1) y axis moves down so that is 1-5 which is negative 4

Step-by-step explanation:

Zielflug [23.3K]3 years ago
6 0

Answer:

Step-by-step explanation:

A(4,1),B(3,2),C(1,1)

Reflection over y-axis (x,y)→(-x,y)

A'(-4,1),B'(-3,2),C'(-1,1)

Translation 5 units down (x,y)→(x,y-5)

A"(-4,-4),B"(-3,-3),C"(-1,-4)

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Tom works 12 hours a day at a café. He is paid $8 an hour. How much<br> money is he paid in 10 days?
Masja [62]

Answer:

Tom will be paid $140 in 10 days

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Will give brainliest to correct answer
tresset_1 [31]
All real numbers except 0
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3 years ago
A tire manufacturer is interested in testing the fuel economy for two different tread patterns. Tires of each tread type are dri
Minchanka [31]

Using the t-distribution, it is found that the 99% confidence interval for the difference is (0.058, 3.462).

We are given the <u>standard deviation for the samples</u>, hence, the t-distribution is used to solve this question.

The standard errors are given by:

s_A = \frac{1.79}{\sqrt{18}} = 0.4219

s_B = \frac{1.95}{\sqrt{18}} = 0.4596

For the distribution of differences, the <u>mean and the standard error</u> are given by:

\overline{x} = \mu_A - \mu_B = 23.95 - 22.19 = 1.76

s = \sqrt{0.4219^2 + 0.4596^2} = 0.6239

The interval is given by:

\overline{x} \pm ts

The critical value for a <u>two-tailed 99% confidence interval</u> with 18 + 18 - 2 = <u>34 df</u> is t = 2.7284.

Then:

\overline{x} - ts = 1.76 - 2.7284(0.6239) = 0.058

\overline{x} + ts = 1.76 + 2.7284(0.6239) = 3.462

The 99% confidence interval for the difference is (0.058, 3.462).

For more on the t-distribution, you can check brainly.com/question/16162795

3 0
3 years ago
Can some tell me the answer for 6a and b please!
Allushta [10]
6a.
output y     differences
0
                          3
3
                          3
6
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9
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3 0
4 years ago
Mike and Teegan each measured the volume of the 16-ounce bottle three times. They recorded their measurements as shown. Mike: 16
-BARSIC- [3]

Answer:

The correct option is;

Mike's measurement are more precise and more accurate

Step-by-step explanation:

The given information are;

The mass of the measured bottle = 16-ounce

The record of the measurements made by Mike are;

16.4 oz

15.2 oz

15.8 oz

The record of the measurements made by Teegan are;

16.34 oz

16.59 oz

15.13 oz

From the two measurements, we have;

The precision of a measurement depends on how close the values of the measurement are to one another, therefore, we have;

For Mike, the precision is given as follows

16.4 - 15.2 = 1.2

16.4 - 15.8 = 0.6

15.8 - 15.2 = 0.6

Total difference = 1.2 + 0.6 + 0.6 = 2.4

For Teegan , the precision is given as follows

16.59 - 16.34 = 0.25

16.59 - 15.13 = 1.46

16.34 - 15.13 = 1.21

Total difference = 0.25 + 1.46 + 1.21 = 2.92

Therefore, Mike's measurements are more precise than Teegan's measurements

The accuracy of the measurement is the amount of closeness the measurements are to a given value

In the question, the given value is 16-ounces of the volume of the bottle

Therefore, by the mean absolute deviation from the 16-ounce of the bottle, we have;

For Mike;

Mean \ absolute  \ deviation = \dfrac{\left | 16.4 - 16 \right | + \left | 15.2 - 16 \right | + \left | 15.8 - 16 \right | }{3} = 0.533

For Teegan, we have;

Mean \ absolute  \ deviation = \dfrac{\left | 16.34 - 16 \right | + \left | 16.59 - 16 \right | + \left | 15.13 - 16 \right | }{3} = 0.6

Therefore, Mike's measurement is more accurate than Teegan's measurement.

Which gives;

Mike's measurement are more precise and more accurate.

9 0
3 years ago
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