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borishaifa [10]
2 years ago
10

Pls help me. Is the answer 0???

Mathematics
1 answer:
vekshin12 years ago
3 0

Answer:

Well, yes it is supposed to be 0

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Can anyone help me with my algebra homework please ?
Vitek1552 [10]

Answer:

She will practice 2.5 for week four

Step-by-step explanation:

The table is going by 0.5 so I added 0.5 +2 =2.5

4 0
3 years ago
Find the solution of these two equations. Y=1/5x-7 and y=-x-1
marusya05 [52]

Answer:For the first one it would be x=35

And the 2nd one would just be x=-1

Step-by-step explanation:

7 0
2 years ago
This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
3 years ago
Integer Basics
Furkat [3]
Can you retype whatever you’re asking in this please?
7 0
3 years ago
Help me pleaseeee asap
sdas [7]

Answer:

5089.4cm³ (rounded to 1 d.p.)

Step-by-step explanation:

Volume of cylinder = \pi × r² × h

Volume of cylinder = \pi × 9² × 20

                                = 1620\pi

                                = 5089.4cm³ (rounded to 1 d.p.)

4 0
2 years ago
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