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nasty-shy [4]
3 years ago
14

Please solve: c + (4 – 3c) – 2 = 0

Mathematics
1 answer:
ahrayia [7]3 years ago
4 0
Ok so first distribute invisible 1
c+1(4-3c)-2=0
c+4-3c-2=0
group like terms
c-3c+4-2=0
add like terms
-2c+2=0
minus 2 from both sides
-2c=-2
divide both sides by -2
c=1
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sertanlavr [38]

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3 years ago
Find the distance between points A (10,-1) and B (-2,5). Round to the nearest tenth
bija089 [108]

Answer:

<h2>The answer is 13.4 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

A (10,-1) and B (-2,5)

The distance is

|AB|  =  \sqrt{ ({10 + 2})^{2} +  ({ - 1 - 5})^{2}  }  \\  =  \sqrt{ {12}^{2}  +  ({ - 6})^{2} }  \\  =  \sqrt{144 + 36}  \:  \:  \:  \:  \:  \:  \:   \\  =  \sqrt{180}  \\  = 6 \sqrt{5}  \:  \:  \\  =13.416407

We have the final answer as

<h3>13.4 units to the nearest tenth</h3>

Hope this helps you

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3 years ago
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e-lub [12.9K]

Answer:

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Step-by-step explanation:

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