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sleet_krkn [62]
3 years ago
12

The ages of dogs at an animal shelter are normally distributed with a mean of 3.9 years and a standard deviation of 1.2 years.

Mathematics
1 answer:
Aleks [24]3 years ago
3 0

Answer:

<u>The correct answer is A.  1.86 years</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean of the dogs at an animal shelter = 3.9 years

Standard deviation = 1.2 years

2. What is the age of a dog at the shelter with a z-score of −1.7 ?

Let's recall that z-score in a normal distribution, positive or negative, is the number of times of the standard deviation a certain element is from the mean. If the element is below the mean, then the z-score is negative and if it's above the mean, then the z-score is positive.

Therefore, a z-score of - 1.7 for the ages of dogs is:

-1.7 * 1.2 = -2.04

Now, we calculate the value using the mean, this way:

3.9 + -2.04 = 3.9 - 2.04 = 1.86

<u>The correct answer is A.  1.86 years</u>

Note: Same answer to question 14270011, answered by me today.

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AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

a)

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So, this integral is convergent.

b)

\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\

So, this integral is divergent.

c)

\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\

So, this integral is divergent.

4 0
3 years ago
The diameter of a circle is 4 cm. Which equation can be used to find its circumference?
Leya [2.2K]

Answer:

pi times 4

Step-by-step explanation:

Circumference: pi times diameter (pi)(d) or pi times 2 times the radius (pi)(2r)

5 0
3 years ago
Read 2 more answers
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

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Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
Using the distributive property and combining like terms to simplify the expression.
soldi70 [24.7K]

Answer:

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Step-by-step explanation:

-5 (x + 2) + 5 (x -5)

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Expand once more:

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6 0
3 years ago
United Blood Services is a blood bank that serves more than 500 hospitals in 18 states. According to their website, a person wit
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Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

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15% of people have Rh- factor

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This is

P(A \cap B) = P(A) + P(B) - P(A \cup B)

With what we have

P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06

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b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

6 0
3 years ago
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