The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula:

Were

is the area in square kilometers

is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so

. Lets replace that value in our formula to find

:

Now, to find the population density of the filed, we are going to use the population density formula:

where

is the population density in <span>in burrows per square kilometer
</span>

is the number of burrows

is the are of the field
We know that

and

, so lets replace those values in our formula:


We can conclude that the <span>density of prairie dog burrows is approximately
2444 burrws per square kilometer.</span>
Answer is 49
Formula is b^2-4(ac)
3^2-4(2*-5) while a=2, b=3, c=-5
9-4(2*-5)
9-4(-10)
9+40
49
Hope this helps!
Hi there! The answer is 15 minutes.
Walking 4 miles per hour means that it takes you 60 minutes to walk 4 miles. To find the time it takes you to walk 1 mile, we must divide both sides by 4.
4 miles equals 60 minutes.
1 mile equals 60 / 4 = 15 minutes.
The answer is 15 minutes.
Answer:
5.
x + 2(x + 1) = 8 --> x = 2
y = 2 + 1 = 3
7.
3(9 + 2y) + 5y = 20 --> y = -7/11
x = 9 + 2(-7/11) = 85/11
9.
3(-1 - 2y) + 5y = -1 --> y = -2
x = -1 - 2(-2) = 3
Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula,
= a + (n-1)d
here,
is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5