Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data, 
= 5.5 mins
Standard deviation, 
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒ 
...raw score,
= 
⇒ Plugging the values.
⇒ 
⇒ 
For raw score 5.5 the z score is.
⇒ 
⇒ 
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒ 
⇒ 
and 
.<em>..from z -score table.</em>
⇒ 
⇒ 
To find the percentage we have to multiply with 100.
⇒ 
⇒ 
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
6 - x = 2(x - 6)
the first step, following PEMDAS, is to distribute the 2 to the inside of your parentheses:
6 - x = 2x - 12 ... subtract 2x
6 - 3x = -12 ... subtract 6
-3x = -18 ... divide by -3
x = 6 is the answer
Looking at number 4, you first have to look at the information that you have:
On tuesday he practiced for 1 5/6 hrs
Monday he practiced for 7/10 hrs
He is supposed to practice for 1 1/4 hr.
You could write questions like:
How much more did Marco practice on Tuesday than he is supposed to practice?
This works because it does indeed involve subtraction, you would be subtracting the amount that he should have practiced from the amount of time that he did practice.
If I didn't answer the question, please message me and I will clarify!
-x>-7 is the answer the line
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