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3 years ago

Write a word problem about equal grups and act it out to solve.

Mathematics

2 answers:

Mashcka [7]3 years ago

7 0

Yes they are correcy

Neko [114]3 years ago

3 0

If i had 6 red rocks and 6 blue rocks i would add them to get 12 rocks

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Kate has a kite with the dimensions shown below. What is the value of X?

sergij07 [2.7K]

Hey there! :D

We will use the properties of similar triangles to figure this out.

We will use two triangles inside the kite, with sides with the value of "x".

Smaller triangle:

Smaller side= 11

Bottom side= x

Bigger triangle:

Smaller side= x

Bottom side= 25

$\frac{11}{x} = \frac{x}{25}$

Cross multiply.

25*11= 275

x*x= $x^{2}$

Find the square root.

√275= 16.583....

Or 5√11.

I hope this helps!
~kaikers

6 0

3 years ago

PLEASE HELP, GIVING 55 POINTS IF YOU ANSWER (08.03/08.05 MC) A pair of equations is shown below: y = 3x − 5 y = 6x − 8 Part A: E

Andrew [12]

Answer:

A. (1, -2)

B. the lines intersect at the solution point: (1, -2).

Step-by-step explanation:

A. The equations can be solve by substitution by using the y-expression provided by one of them to substitute for y in the other.

This gives ...

3x -5 = 6x -8

Adding 8-3x to both sides, we get ...

3 = 3x

Dividing both sides by 3 gives ...

1 = x

Substituting this value into the first equation, we can find y:

y = 3(1) -5 = -2

The solution is (x, y) = (1, -2).

B. The lines intersect at the solution point, the point that satisfies both equations simultaneously. That point is (1, -2).

8 0

3 years ago

Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

Read 2 more answers

Divide £48 in the ratio 7 : 5

Phoenix [80]

Given there are 12 parts in the ratio, we would divide 48 by 12 which equals 4. So, the ratio would be 28:20.

6 0

4 years ago

Read 2 more answers

Arthur took out a 20 year loan for $60,000 at an APR of 4.4% compounded monthly. Approximately how munch would save if he paid i

Eduardwww [97]

Monthly payments, P = {R/12*A}/{1- (1+R/12)^-12n}

Where R = APR = 4.4% = 0.044, A = Amount borrowed = $60,000, n = Time the loan will be repaid

For 20 years, n = 20 years
P1 = {0.044/12*60000}/{1- (1+0.044/12)^-12*20} = $376.36

Total amount to be paid in 20 years, A1 = 376.36*20*12 = $90,326.30

For 3 years early, n = 17 year
P2 = {0.044/12*60,000}/{1-(1+0.044/12)^-12*17} = $418.22

Total amount to be paid in 17 years, A2 = 418.22*17*12 = $85,316.98

The saving when the loan is paid off 3 year early = A1-A2 = 90,326.30 - 85,316.98 = $5,009.32

Therefore, the approximate amount of savings is A. $4,516.32. This value is lower than the one calculated since the time of repaying the loan does not change. After 17 years, the borrower only clears the remaining amount of the principle amount.

8 0

3 years ago

Read 2 more answers