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3 years ago

Consider this sequence

1 answer:

5 0

Hello,

$u_{1} =1*(8-7)=1*(2*4-(6+1))\\
 u_{2} =2*(10-7)=2*(2*5-(6+2))=2*(2*(4+1)-(6+2))\\
 u_{3} =3*(12-9)=3*(2*6-(6+3))=3*(2*(4+2)-(6+3))\\
 u_{4} =4*(14-10)=4*(2*7-(6+4))=4*(2*(4+3)-(6+4))\\

$

$u_{10}=10*(2*(4+10)-(6+10))\\
=10*(28-16)
$

$...\\\\
u_{n} =n*(2*(n+n-1)-(6+n))\\
=n*(4n-2-6-n)=n(3n-8)\\

$

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Step-by-step explanation:

Previous concepts

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