Answer:
a) Sinusoidal functions are y = a sin [b(x-h)] + k (or)
y = a cos [b(x-h)] + k
Where a is amplitude a= (max-min)/2=(16-2)/2=7
period p= 2π/b
b=2π/30
Horizontal transformation to 10 units right h=10
k= (max+min)/2=(16+2)/2=9
h = 7 cos [π/15(t-10)]+ 9
b) t=10min=600 sec
substitue in the above equation
h=5.5m
Answer:
<OPQ = 23 degrees
Step-by-step explanation:
Given
Interior angles m∠PNO=(x+14) and m∠NOP=(x−1)
Exterior angle = m<OPQ = (5x-2)
The sum of interior angles is equal to the exterior angle, that is;
m∠PNO+m∠NOP = m<OPQ
x+14 + x-1 = 5x-2
2x + 13 = 5x-2
Collect like terms;
2x-5x = -2-13
-3x = -15
x = 15/3
x = 5
Get <OPQ
<OPQ = 5x - 2
<OPQ = 5(5)- 2
<OPQ = 25-2
<OPQ = 23 degrees
