Number 1 is B
Number 2 is also B
Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,
![\frac{BC}{sinA}=\frac{AB}{SinC}](https://tex.z-dn.net/?f=%5Cfrac%7BBC%7D%7BsinA%7D%3D%5Cfrac%7BAB%7D%7BSinC%7D)
![\frac{BC}{sin(18.6)}= \frac{646}{sin(68.4)}](https://tex.z-dn.net/?f=%5Cfrac%7BBC%7D%7Bsin%2818.6%29%7D%3D%20%5Cfrac%7B646%7D%7Bsin%2868.4%29%7D)
![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)
![BC = \frac{646*sin(18.6)}{sin(68.4)}](https://tex.z-dn.net/?f=BC%20%3D%20%5Cfrac%7B646%2Asin%2818.6%29%7D%7Bsin%2868.4%29%7D)
![BC = \frac{646 * 0.3190}{0.9298}](https://tex.z-dn.net/?f=BC%20%3D%20%5Cfrac%7B646%20%2A%200.3190%7D%7B0.9298%7D)
![BC = 221.63](https://tex.z-dn.net/?f=BC%20%3D%20221.63)
meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
I found the correct image that accompanies this problem and edited it with my answers.. Pls. see attachment.
Based on the attachment, the correct statements are:
<span>1) DO,2 (x,y) = (2x, 2y)
2) Side Q'S' lies on a line with a slope of -1.
Q'(-6,6) S'(-2,2)
m = y1 - y2 / x1 - x2
m = 6 - 2 / -6 - (-2)
m = 4 / -4
m = -1
</span><span>5) The distance from Q' to the origin is twice the distance from Q to the origin.
</span>
Answer:
6
Step-by-step explanation:
2+4 = 6
..............