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forsale [732]
4 years ago
15

Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the graph of the g

iven equation (-1,-2),3x-y=4
Mathematics
1 answer:
dangina [55]4 years ago
3 0

Answer:

y = 3x + 1

Step-by-step explanation:

First, turn 3x - y = 4 around into Slope-Intercept Form:

3x - y = 4

-3x - 3x

________

−y = −3x + 4

y = 3x - 4

The <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] is 3:

−2 = 3[−1] + b

−3

1 = b

y = 3x + 1

* Parallel lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>], so 3 remains the way it is.

I am joyous to assist you anytime.

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Answer: B?

Step-by-step explanation:

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Which fraction and equivalent decimal correctly shows the ratio of shaded circles to all circles
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Answer:


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4 0
3 years ago
What are the coordinates of the vertices of the pre-image given? ry= −x ◦ T1, −2(x, y) 
nataly862011 [7]
<h3><u>Answer:</u></h3>

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

<h3><u>Step-by-step explanation:</u></h3>

We have to find the  coordinates of the vertices of the pre-image given?

Ry= −x ◦ T_1, −2(x, y)

i.e. we have to find the composition of reflection along the line y=-x and translation with the rule:

(x,y) → (x+1,y-2)

Now we have coordinates of A",B",C" and D" as:

A"(-4,-2)

B"(-2,-1)

C"(-2,-4)

D"(-4,-3)

Now we are asked to find the coordinates of the pre-image.

Also when any point is reflected along y=-x then the point is transformed to:

(x,y) → (-y,-x)

Let A,B,C and D are the points of the pre-image.

Hence, the coordinates of the pre-image are given as:

so, the transformation is given as:

A→A'→A"

B→B'→B"

C→C'→C"

D→D'→D"

Where A',B',C',D' represents the transformation after translation and A",B",C",D" represents the transformation after reflection as well.

The coordinates of A' are (2,4)

B' are (1,2)

C' are (4,2)

and D' are (3,4)

Now, the coordinates of pre-image are given as:

A'(x,y)  → A(x-1,y+2)=A(1,6)

B'(x,y)  → B(x-1,y+2)=B(0,4)

C'(x,y)  → C(x-1,y+2)=C(3,4)

and D'(x,y)  → D(x-1,y+2)=D(2,6)

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

4 0
3 years ago
Alguien me puede ayudar porfavor en la pregunta 28
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no habla espanol muy bueno pero voy a tratar a ayudarlo. podemos simplificar 6/15; simplemente divide por 3. el resultado es 2/5, no 3/5. entonces, 6/15 no es equivelente al 3/5.
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