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Igoryamba
3 years ago
7

Help me on the last question please asap

Mathematics
1 answer:
bogdanovich [222]3 years ago
7 0
Is the question your asking the one at the bottom
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What’s the answer to this question???????
saveliy_v [14]

Answer:

26

Step-by-step explanation:

if YZ bisects VW then VX = XW

if VX = 26 then XW = 26 also

5 0
3 years ago
Emily spent a total of 38.04 on four CDs if each CD cost the same amount what is a reasonable amount for each CD explain why you
mojhsa [17]
To find the cost of one CD, we divide 38.04 by 4

38.04 ÷ 4 = 9.51

The answer is reasonable because it's an accurate answer.
6 0
3 years ago
Read 2 more answers
Which expression is equivalent to the one in the picture?
Ne4ueva [31]

Answer:

d.

Step-by-step explanation:

To convert a root to a fraction in the exponent, remember this rule:

\sqrt[n]{a^{m}}=a^{\frac{m}{n}}

The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.

In this question, the index is 4.

The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.

\sqrt[4]{16x^{15}y^{17}} = (\sqrt[4]{16})(\sqrt[4]{x^{15}})(\sqrt[4]{y^{17}}) = (2)(x^{\frac{15}{4}}})(y^{\frac{17}{4}}) = 2x^{\frac{15}{4}}}y^{\frac{17}{4}}

To find the quad root of 16, input this into your calculator. Since 2⁴ = 16, \sqrt[4]{16} = 2.

For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.

2x^{\frac{15}{4}}y^{\frac{17}{4}}

5 0
3 years ago
Name a pair of perpendicular lines: <br>is line BC and AJ perpendicular: explain ​
wel
A pair of perpendicular lines would be line CF and line AJ.

Line BC and line AJ are NOT perpendicular because when a pair of lines are perpendicular, all angles become 90 degrees. It is obvious, in the case, if you were to slide line BC on top of line AJ, the angles will not equal 90 degrees.
8 0
3 years ago
Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y

a)

we know that \int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1

therefore \int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1

on integrating we get

c=(1/6640)

b)

P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

on doing the integration we get

                        =0.37349

c)

marginal density of X is

f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx

on doing integration we get

f(y)=\frac{(y+40.5)}{83}

d)

P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

solve the above integration we get the answer

e)

P(X>20, 0

solve the above integration we get the answer

f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

4 0
3 years ago
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