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2 years ago

Y=1/2x what are the coordinates PLEASE HELP !!!!!!!

Mathematics

2 answers:

iris [78.8K]2 years ago

6 0

Y=1/2x represents a Linear equation from the form y = mx + b (In our case, b = 0 so we don't put it).
In such a form, m represents the slope of the equation. And b represents the y-intercept of the equation. While y and x represents the coordinates of 2 points.
In y=1/2x, m=1/2; b = 0. So the coordinates are y and x.
I've added a graph of the equation y= 1/2x under the answer.

Hope this Helps! :)

Gre4nikov [31]2 years ago

3 0

U need x also srry u cant complete ure answer

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Solve for Y........................

aivan3 [116]

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20 squared is 400
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3 years ago

2abc - 3ab if a=2 b=-3 and c=4

Margarita [4]

2abc - 3ab ║ 2 (2) (3) (4) - 3 (2) (3)

You would multiply and the products - you are going to subtract
2 × 2 × 3 × 4 = 48
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answer: 30

7 0

2 years ago

Read 2 more answers

Thaddeus models the number of hours of daylight in his town as

AfilCa [17]

Option (A) : least: 10 hours; greatest: 14 hours

The function f(x) = sin x has all real numbers in its domain, but its range is

−1 ≤ sin x ≤ 1.

How to solve such range questions?

Such questions in which every term is in addition and its range is asked is simplest ones to solve if we know the range of each of term. This can be seen from this question

Given: d(t) = 2sin(xt) + 12

= −1 ≤ sin (xt) ≤ 1.

= −2≤ 2 sin (xt) ≤ 2.

= 10 ≤ 2sin (xt) + 12 ≤ 14

= 10 ≤d(t) ≤ 14

Thus least: 10 hours; greatest: 14 hours

Learn more about range of trigonometric ratios here :

brainly.com/question/14304883

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6 0

2 years ago

Last month, you worked 41 hours the first week, 49 hours the second week, 48 hours the third week, and 46 hours the last week. F

inysia [295]

Answer:

46 hours

Step-by-step explanation:

1. add all the hours you've worked (41+49+48+46=184)

2. divide the sum by the number of weeks (184/4=46)

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3 years ago

Find the number b such that the line y = b divides the region bounded by the curves x = y^2 − 1 and the y-axis into 2 regions wi

77julia77 [94]

Because of the symmetry, we can just go from x=0 to x=2 to find the area between
y = x^2 and y = 4 

that area = ∫4-x^2 dx from 0 to 2 
= [4x - (1/3)x^3] from 0 to 2 
= 8 - 8/3 - 0 
= 16/3 

so when y = b 
x= √b 
and we have the area as 
∫(b - x^2) dx from 0 to √b 
= [b x - (1/3)x^3] from 0 to √b 
= b√b - (1/3)b√b - 0 

(2/3)b√b = 8/3 
b√b =4 
square both sides 
b^3 = 16 
b = 16^(1/3) = 2 cuberoot(2) 
or appr 2.52

7 0

3 years ago