Using the z-table, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.
First, solve for the z-score using the formula below.
z-score = (x – μ) / σ
where x = individual data value = 100
μ = mean = 125
σ = standard deviation = 18
z-score = (100 – 125) / 18
z-score = (-25) / 18
z-score = -1.39
Find the probability that corresponds to the z-score in the z-table. (see attached images)
-1.39 - (-1.3) : -1.4 - (-1.3) = x - 0.0968 : 0.0808 - 0.0968
-0.09 : -0.1 = x - 0.0968 : -0.016
x - 0.0968 = -0.09(-0.016)/-0.1
x = -0.0144 + 0.0968
x = 0.0824
x = 0.0824
Hence, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
Learn more about probability here: brainly.com/question/26822684
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The property used to rewrite the given expression is product property.
Answer: Option A
<u>Step-by-step explanation:</u>
Given equation:

The sum of the two logarithms of two quantities (on the same basis) corresponds to the logarithm of their product on the same basis. The product log is equal to the log’s sum of the factors.

There are several rules that you can use to solve logarithmic equations. One of these guidelines is the logarithmic products rule that you can use to differentiate complex protocols in different ways. Different values that can be valuable are the quota principle and the logarithm rule. The logarithmic products rule is essential and is regularly used in analysis to control logs and simplify baseline conditions.
Answer:
Its about 678.584
Step-by-step explanation:
First plug in your given info so put 6 for the r and 6 for thr h. the r stands for radius and the h stands for hight. Then solve for 6 squared which is just 6*6 which is 36 then multiply that by 6 to get 216. then multiply 216 by pie to get your answer.
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Answer:

Step-by-step explanation:
<u>Sequential Operations
</u>
Mathematical operations can be done in sequence or in batches if they are of the same type. For example, we can add many terms in one single operation, but we cannot add and multiply in one go, because there are priorities when dealing with products and sums. Same happens with powers.
In our problem we are required to perform a sequence of operations like follows
Add s to t:

Add the result to r

Raise what you have to the 7th power

This is the final result