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3 years ago

GUYS I LEVELED UP TO ACE!!!!

Advanced Placement (AP)

2 answers:

katrin2010 [14]3 years ago

4 0

Congrats!! That must make you feel really good!

andrey2020 [161]3 years ago

3 0

Yay!

Congratulations, keep answering questions and you will get a even higher rank.

Good Luck :)

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In one paragraph, describe how you might use elaboration to remember a piece of important information.

mote1985 [20]

I would connect my information with both topics and try to figure out how the connect

6 0

3 years ago

Knowledge about the general plot of a novel one has read is probably stored in long-term memory as:

Hunter-Best [27]

The answer is: propositions

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3 years ago

Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th

lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

$C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2$

Finding the boundaries of the function gives;

$0\times e^{4-0^2} = 0$ and $2\times e^{4-2^2} = 2$

At t = 1, we have $1\times e^{4-1^2} = e^{3} = 20.086$

We find the maximum point as follows;

$\frac{\mathrm{d} \left (t\times e^{4-t^2} \right )}{\mathrm{d} x}=0$

From which we have;

$\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0$

$e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0$

$e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\$

$e^{4-t^2}=0$ or $(1 - 2\times t^2 })=0$

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for 0 ≤ t ≤ 0 1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

8 0

3 years ago

A receptor protein in the plasma membrane will not bind to just any chemical in the extracellular fluid, but only to certain one

adoni [48]

I believe the answer you're looking for is "Specificity".

<em>(Please mark this answer as Brainliest and leave a Thanks if I helped you!)</em>

6 0

3 years ago

ADVICE: I have a class in which there are 5 teachers and 15 students, and for the past 3 days I've been trying to receive help a

nlexa [21]

Answer:

that should mean 3 students per teacher. i would reccomend sending an email or having a conference on the attention given to you something like that

Explanation:

7 0

3 years ago

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