All categories

3 years ago

The area of a square shaped yard is 201.5 ft2. Which measurement is closest to the side length of this yard in feet?

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

8 0

Answer:

a = 14.19 feet

Step-by-step explanation:

Given that,

The area of a square shaped yard is 201.5 ft²

We need to find the side length of this yard in feet.

The area of a square shaped object is given by :

A = a², a is the side length of the object

Put A = 201.5 ft² in above formula,

$201.5=a^2\\\\a=\sqrt{201.5 } \\\\a=14.19\ \text{feet}$

So, the side of the square yard is 14.19 feet.

You might be interested in

Could I get some help? QUESTION: This table shows the profit for a company (in millions of dollars) in different years.

Pani-rosa [81]

Answer:

17 million

Step-by-step explanation:

-0.34( $8^{2}$ ) + 4.43(8) + 3.46

-21.76 + 35.44 + 3.46

13.68 + 3.46

17.14

Answer: C 17 million

Have an amazing day!

<u><em>PLEASE RATE!</em></u>

7 0

2 years ago

Help me, Thanks!!

Marrrta [24]

2.) dT/dt = -t^2 + 3t

dT = (-t^2 + 3t)dt

T = -t^3/3 + 3t^2/2 + C

at 4:00 AM

80 = -4^3/3 + 3*4^2/2 + C

C = 80 + 4^3/3 - 3*4^2/2

C = 77.33

T = -t^3/3 + 3t^2/2 + 77.33

at 8:00 AM

T = -8^3/3 + 3*8^2/2 + 77.33

T = 2.67 deg

5 0

3 years ago

Needddddddd help super badly

nexus9112 [7]

Answer:

628.32

Step-by-step explanation:

Volume of a cone = 1/3 π r² h

4 0

3 years ago

What is the value of 5(a + b) when a=1 and b=6

lana [24]

Answer: 35

Step-by-step explanation:

We substitute a for 1 and b for 6.

5(1+6)=5(7)=35

5 0

3 years ago

Salska and colleagues (2008) studied height preferences among dating partners. In their first study, they reviewed Yahoo persona

lisov135 [29]

Answer:

Step-by-step explanation:

The larger standard deviation, the greater the variability. So even before looking at the data, we can eliminate a) and c).

The standard deviations of men's preference of shortest and tallest acceptable height (3.7 and 2.7, respectively) were more than the standard deviations of women's preference of shortest and tallest acceptable height (2.6 and 2.2, respectively).

So men showed greater variability overall because the standard deviations for men were larger than for women. Answer D.

6 0

3 years ago