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Nostrana [21]
3 years ago
8

X=5, y=7 X=6, y=9 X=6, y=8 X=7, y=10

Mathematics
1 answer:
Zinaida [17]3 years ago
3 0
The answer is x=6, y=9.

EXPLANATION

Segments QT and ST are congruent to each other because the diagonals meet at point T, which bisects them. Segments RT and PT are also congruent.

Deriving from this, we say

QT = ST
PT = RT

Choose one of these diagonals, so we can simply find one value of x we can substitute for another diagonal.

So, in this case, we use first PT = RT

PT = RT
2x = y+3
x=(y+3)/2

Now, we will plug in the value of x to the equation showing the congruence of segments QT = ST.

QT = ST
3x = 2y
3(y+3)/2 = 2y
3y+9/2 = 2y
(3y+9/2 = 2y)2
3y+9 = 4y
y = 9

Now, we have the value of y, substitute it to any of the two equations we had for the two diagonals.

2x = y+3
2x = 9+3
2x = 12
x = 6

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Answer:

a) <em>The equation</em> (10s + 8w) <em>represents </em><em>the </em><em>calories </em><em>Bridget </em><em>ate </em><em>on </em><em>Monday </em><em>and </em><em>the </em><em>equation</em> (20s + w) <em>represents </em><em>the </em><em>calories</em><em> </em><em>she </em><em>ate</em><em> </em><em>the </em><em>next </em><em>day.</em>

<em>b)</em><em> </em><em>The </em><em>number </em><em>of </em><em>calories</em><em> </em><em>in </em><em>each </em><em>strawberry</em><em> </em><em>is </em>4 <em>and </em><em>the </em><em>number </em><em>of </em><em>calories </em><em>in </em><em>each </em><em>vanilla</em><em> </em><em>wafer</em><em> cookie</em><em> </em><em>is </em>19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is <em>s</em> and the number of calories in a vanilla wafer cookie is <em>w </em>, the number of calories Bridget ate on Monday is <em>10s + 8w</em><em>.</em><em> </em>The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s<em> + w</em>.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

20s + 16w - 20s - w = 285

15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

Now, we can solve for s using equation 2.

20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

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