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Darina [25.2K]
4 years ago
12

How to create a hacking program on java?

Computers and Technology
2 answers:
Paraphin [41]4 years ago
6 0

Well I wouldn't get into stuff like that BUT if you really want to know you can make code to crash computers by over running the CPU. I'm not going to put it in this comment because I don't want you to do it as it can get you into trouble! You can also make a RAT( Remote access tool ), PLEASE DONT DO ANY OF THIS. You can also make programs in java to steal passwords off of chrome Firefox and other browsers and send them over FTP to you. As saying again please don't do any of this as getting into stuff like this is... not the best(that's why i'm not providing code!)

Leviafan [203]4 years ago
4 0

Answer: You can script or use coding you can buy them if you don't know but you might get in trouble and it will take a lot of time, sometimes

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A shot sequence is the time between when a shot is shot and when it lands
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4 years ago
Write a program that prints the day number of the year, given the date in the form month-day-year. For example, if the input is
vlabodo [156]

Answer:

C++:

C++ Code:

#include <iostream>

#include <string>

using namespace std;

struct date

{

  int d,m,y;

};

int isLeap(int y)

{

  if(y%100==0)

  {

      if(y%400==0)

      return 1;

      return 0;

  }

  if(y%4==0)

  return 1;

  return 0;

}

int day_no(date D)

{

  int m = D.m;

  int y = D.y;

  int d = D.d;

  int i;

  int mn[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};

  for(i=0;i<m;i++)

  {

      d += mn[i];

  }

  if(isLeap(y))

  {

      if(m>2)

      d++;

  }

  return d;

}

date get_info(string s)

{

  date D;

  int i,p1,p2,l = s.length();

  for(i=0;i<l;i++)

  {

      if(s[i] == '-')

      {

      p1 = i;

      break ;

      }

  }

  for(i=p1+1;i<l;i++)

  {

      if(s[i] == '-')

      {

      p2 = i;

      break ;

      }

  }

 

  D.m = 0;

  for(i=0;i<p1;i++)

  D.m = (D.m)*10 + (s[i]-'0');

 

  D.d = 0;

  for(i=p1+1;i<p2;i++)

  D.d = (D.d)*10 + (s[i]-'0');

 

  D.y = 0;

  for(i=p2+1;i<l;i++)

  D.y = (D.y)*10 + (s[i]-'0');

 

  return D;

 

}

int main()

{

  string s1 = "4-5-2008";

  string s2 = "12-30-1995";

  string s3 = "6-21-2000";

  string s4 = "1-31-1500";

  string s5 = "7-19-1983";

  string s6 = "2-29-1976";

 

  cout<<"Date\t\tDay no\n\n";

  cout<<s1<<"\t"<<day_no(get_info(s1))<<endl;

  cout<<s2<<"\t"<<day_no(get_info(s2))<<endl;

  cout<<s3<<"\t"<<day_no(get_info(s3))<<endl;

  cout<<s4<<"\t"<<day_no(get_info(s4))<<endl;

  cout<<s5<<"\t"<<day_no(get_info(s5))<<endl;

  cout<<s6<<"\t"<<day_no(get_info(s6))<<endl;

 

 

  return 0;

}

Explanation:

4 0
3 years ago
Paul has been working long hours. He is tired and distracted by family issues, so he has not been doing record updates regularly
mina [271]

Answer:

Accidental data loss

Explanation:

Accidental data loss -

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The information can be lost due to sudden power cut , natural calamities like fires , flood earthquake etc. , problem in hard disk etc.

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The correct option is accidental data loss.

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David is selling his art work. He wants to figure out how much he should charge for each painting to make a 20 percent profit. H
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Answer:

create a spreadsheet that totals the cost and calculates 120 percent of the total cost

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(Count positive and negative numbers and compute the average of numbers) Write a program that reads an unspecified number of int
Papessa [141]

Answer:

Explanation:

Sorry it  is in Java, though you can covert it using converter

public class Exercise {

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int positives = 0;  // Count the number of positive numbers

 int negatives = 0;  // Count the number of negative numbers

 int count = 0;   // Count all numbers

 double total = 0;  // Accumulate a totol

 // Promopt the user to enter an integer or 0 to exit

 System.out.print("Enter an integer, the input ends if it is 0: ");

 int number = input.nextInt();

 if (number == 0) { // Test for sentinel value

  System.out.println("No numbers are entered except 0");

  System.exit(1);

 }

 while (number != 0) {// Test for sentinel value

  if (number > 0)

   positives++; // Increase positives

  else

   negatives++; // Increase negatives

  total += number; // Accumulate total

  count++;    // Increase the count

  number = input.nextInt();

 }

 // Calculate the average

 double average = total / count;

 // Display results

 System.out.println(

  "The number of positive is " + positives +

  "\nThe number of negatives is " + negatives +

  "\nThe total is total " + total +

  "\nThe average is " + average);

}

}

7 0
3 years ago
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