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My name is Ann [436]
3 years ago
15

EDI decreases ______

Computers and Technology
1 answer:
astraxan [27]3 years ago
7 0

Answer:Message length

Explanation:Electronic data interchange(EDI) is the communication path that is established for the interchanging of business documents between the connected organization and partners electronically.

It has several benefits such as security maintenance , increasing productivity, enhancing the customer -related services and also minimizing the length of the data so that it can have accuracy and be on-point rather than being unnecessarily detailed.

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An organization is implementing a preselected baseline of security controls, but finds not all of the controls apply. What shoul
WINSTONCH [101]

The answer is Tailoring the baseline to their needs.

After an organization selects applicable security control baseline but finds not all of the controls apply, it initiates a tailoring process to modify the controls appropriately and more closely with specific conditions related to organizational missions, information systems or environments of operation. It is an integral part of the security control selection and specification and involves risk management processes like assessing, responding to, and framing.

8 0
3 years ago
Default color html ​
Marrrta [24]

Answer:

black for font...

and

white for bg color

Explanation:

i think this is enough for ur question...

3 0
3 years ago
Draw a timeline for each of the following scheduling algorithms. (It may be helpful to first compute a start and finish time for
12345 [234]

Answer:

See explanation below

Explanation:

Previos concepts

First Come First Serve (FCFS) "is an operating system scheduling algorithm that automatically executes queued requests and processes in order of their arrival".

Shortest job next (SJN), or the shortest job first (SJF) or shortest "is a scheduling policy that selects for execution the waiting process with the smallest execution time".

Shortest remaining time (SRF) "is a scheduling method that is a preemptive version of shortest job next scheduling'".

Round robin (RR) is an algorithm where the time parts "are assigned to each process in equal portions and in circular order, handling all processes without priority"

Solution for the problem

Assuming the dataset given on the plot attached.

Part a

For this algorithm the result would be:

Job A   0-6

Job B   6-(6+3) = 6-9

Job C   9-(9+1) = 9-10

Job D   10-(10+4) = 10-14

Part b

For this algorithm the result would be:

Job A   0-6

Job C   6-(6+1) = 6-7

Job B   7-(7+3) = 7-10

Job D   10-(10+4) = 10-14

Part c

For this algorithm the result would be:

Job A   0-1  until 14

Job B   2-(2+3) = 2-5

Job C   3-(3+2) = 3-5

Job D   9-(9+5) = 9-14

Part d

For this algorithm the result would be:

Job A   0-2 , 7-9, 12-14

Job B   2-4, 9-10

Job C   4-(4+1) = 4-5

Job D   5-7, 10-12

8 0
3 years ago
Write a user-defined function that calculates the GPA. For the function name and arguments, use the following: The input argumen
QveST [7]

Answer:

#include <iostream>

#include <vector>

using namespace std;

void calGPA();

vector<int> g;

vector<int> h;

int main(){

   char pushMore = 'y';

   int fg, fh;

   for (;;){

       if (pushMore == 'n'){

           break;

       } else{

           cout<< "Enter integer for grade: ";

           cin>> fg;

           cout<< "Enter integer for credit hours: ";

           cin>> fh;

           g.push_back(fg);

           h.push_back(fh);

           cout<< "Do you want to add more grade and credit hours? y/n: ";

           cin>> pushMore;

       }

   }

   calGPA();

}

void calGPA(){

   double total = 0, GPA;

   for (int i = 0; i < g.size(); ++i) {

        total +=  g.at(i) * h.at(i) ;

   }

   cout<< "The GPA is : "<< total/g.size();

}

Explanation:

The C++ source code above defines two vectors 'g' and 'h'. The latter holds the grades of a student while the former holds the credit hours for the subject taken. The void 'calGPA' function calculates and prints the student's GPA.

7 0
3 years ago
To select more than one sketched entity, you need to press and hold down the ________ key on the keyboard while selecting the en
almond37 [142]

Answer:

The answer to this question is Control(ctrl).

Explanation:

We use control(ctrl) key when we need to select multiple entities.

So when we want to select more than one sketched entity we need to press and hold the control key on the keyboard when we are selecting the items.

Hence we conclude that the answer to this question is Control(ctrl).

6 0
4 years ago
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