The answer is Tailoring the baseline to their needs.
After an organization selects applicable security control baseline but finds not all of the controls apply, it initiates a tailoring process to modify the controls appropriately and more closely with specific conditions related to organizational missions, information systems or environments of operation. It is an integral part of the security control selection and specification and involves risk management processes like assessing, responding to, and framing.
Answer:
black for font...
and
white for bg color
Explanation:
i think this is enough for ur question...
Answer:
See explanation below
Explanation:
Previos concepts
First Come First Serve (FCFS) "is an operating system scheduling algorithm that automatically executes queued requests and processes in order of their arrival".
Shortest job next (SJN), or the shortest job first (SJF) or shortest "is a scheduling policy that selects for execution the waiting process with the smallest execution time".
Shortest remaining time (SRF) "is a scheduling method that is a preemptive version of shortest job next scheduling'".
Round robin (RR) is an algorithm where the time parts "are assigned to each process in equal portions and in circular order, handling all processes without priority"
Solution for the problem
Assuming the dataset given on the plot attached.
Part a
For this algorithm the result would be:
Job A 0-6
Job B 6-(6+3) = 6-9
Job C 9-(9+1) = 9-10
Job D 10-(10+4) = 10-14
Part b
For this algorithm the result would be:
Job A 0-6
Job C 6-(6+1) = 6-7
Job B 7-(7+3) = 7-10
Job D 10-(10+4) = 10-14
Part c
For this algorithm the result would be:
Job A 0-1 until 14
Job B 2-(2+3) = 2-5
Job C 3-(3+2) = 3-5
Job D 9-(9+5) = 9-14
Part d
For this algorithm the result would be:
Job A 0-2 , 7-9, 12-14
Job B 2-4, 9-10
Job C 4-(4+1) = 4-5
Job D 5-7, 10-12
Answer:
#include <iostream>
#include <vector>
using namespace std;
void calGPA();
vector<int> g;
vector<int> h;
int main(){
char pushMore = 'y';
int fg, fh;
for (;;){
if (pushMore == 'n'){
break;
} else{
cout<< "Enter integer for grade: ";
cin>> fg;
cout<< "Enter integer for credit hours: ";
cin>> fh;
g.push_back(fg);
h.push_back(fh);
cout<< "Do you want to add more grade and credit hours? y/n: ";
cin>> pushMore;
}
}
calGPA();
}
void calGPA(){
double total = 0, GPA;
for (int i = 0; i < g.size(); ++i) {
total += g.at(i) * h.at(i) ;
}
cout<< "The GPA is : "<< total/g.size();
}
Explanation:
The C++ source code above defines two vectors 'g' and 'h'. The latter holds the grades of a student while the former holds the credit hours for the subject taken. The void 'calGPA' function calculates and prints the student's GPA.
Answer:
The answer to this question is Control(ctrl).
Explanation:
We use control(ctrl) key when we need to select multiple entities.
So when we want to select more than one sketched entity we need to press and hold the control key on the keyboard when we are selecting the items.
Hence we conclude that the answer to this question is Control(ctrl).
