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WINSTONCH [101]
3 years ago
12

Below is a summary of the educational degrees of four applicants to a hospital. The hospital is looking for a Radiologist, an Or

derly, and a Biomedical Engineer.
Summary of Degrees for Applicants Applying to Hospital Careers


Applicant 1
High school diploma, bachelor's degree


Applicant 2
High school diploma, bachelor's degree, master's degree


Applicant 3
High school diploma


Applicant 4
High school diploma, bachelor's degree, doctorate degree

Which applicants would be best qualified for the jobs based on educational level?
Applicant 2 is qualified to be a Radiologist, applicant 1 is qualified to be an Orderly, and applicants 2, 3, and 4 are qualified to be Biomedical Engineers.

Applicant 3 is qualified to be a Radiologist, applicant 2 is qualified to be an Orderly, and applicants 1 and 4 are qualified to be Biomedical Engineers.

Applicant 1 is qualified to be a Radiologist, applicant 4 is qualified to be an Orderly, and applicants 2 and 3 are qualified to be Biomedical Engineers.

Applicant 4 is qualified to be a Radiologist, applicant 3 is qualified to be an Orderly, and applicants 1, 2, and 4 are qualified to be Biomedical Engineers.
Advanced Placement (AP)
2 answers:
neonofarm [45]3 years ago
6 0
<span>Applicant 4 is qualified to be a Radiologist, applicant 3 is qualified to be an Orderly, and applicants 1, 2, and 4 are qualified to be Biomedical Engineers.</span>
vodomira [7]3 years ago
3 0

Answer:

D

Explanation:

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What is the difference between explicit and implicit prejudice? How have these
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Answer:

An explicit attitude is the kind of attitude that you deliberately think about and report. For example, you could tell someone whether or not you like math. Implicit attitudes are positive and negative evaluations that are much less accessible to our conscious awareness and/or control.

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2 years ago
What is the axis of symetry of the function f(x)= -(x+9)(x-2)
Stels [109]

We first need to write the function in standard form.

y = -x^2 - 7x + 18

To find the axis of symmetry, we do -b/2a

The a and b are the coefficients of the x values.

So a would be -1 since -x is same as -1x

Follow that, b would be -7.

Then just plug the values in. - (-7)/2(-1) = -7/2

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5 0
3 years ago
Explain in detail, how you solved the following problem: The first two terms of a sequence are 10 and 20. If each term after the
KIM [24]

Answer:

T_{2020} = 15

Explanation:

Given

T_1 = 10

T_2 = 20

Each term after the second term is the average of all of the preceding terms

Required:

Explain how to solve the 2020th term

Solve the 2020th term

Solving the 2020th term of a sequence using conventional method may be a little bit difficult but in questions like this, it's not.

The very first thing to do is to solve for the third term;

The value of the third term is the value of every other term after the second term of the sequence; So, what I'll do is that I'll assign the value of the third term to the 2020th term

<em>This is proved as follows;</em>

From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

T_{n} = \frac{\sum T{k}}{n-1} ; where: k = 1 .... n -1

<em>Assume n = 3</em>

T_{3} = \frac{T_1 + T_2}{2}

<em>Multiply both sides by 2</em>

2 * T_{3} = \frac{T_1 + T_2}{2} * 2

2T_{3} = T_1 + T_2

<em>Assume n = 4</em>

T_{4} = \frac{T_1 + T_2 + T_3}{3}

T_{4} = \frac{(T_1 + T_2) + T_3}{3}

Substitute 2T_{3} = T_1 + T_2

T_{4} = \frac{2T_3 + T_3}{3}

T_{4} = \frac{3T_3}{3}

T_{4} = T_3

Assume n = 5

T_{5} = \frac{T_1 + T_2 + T_3 +T_4}{4}

T_{5} = \frac{(T_1 + T_2) + T_3 +(T_4)}{4}

Substitute 2T_{3} = T_1 + T_2 and T_{4} = T_3

T_{5} = \frac{2T_3 + T_3 +T_3}{4}

T_{5} = \frac{4T_3}{4}

T_{5} = \frac{(5-1)T_3}{5-1}

<em>Replace 5 with n</em>

T_{n} = \frac{(n-1)T_3}{n-1}

<em>(n-1) will definitely cancel out (n-1); So, we're left with</em>

T_{n} = T_3

Hence,

T_{2020} = T_3

Calculating T_3

T_{3} = \frac{10 + 20}{2}

T_{3} = \frac{30}{2}

T_{3} = 15

Recall that T_{2020} = T_3

T_{2020} = 15

3 0
3 years ago
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