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3 years ago

Need help NOT wanta talk

Mathematics

2 answers:

erik [133]3 years ago

4 0

What can I help you with? Are you okay?

BlackZzzverrR [31]3 years ago

3 0

Your answer is wanna not wanta :):):):):):):)

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Wayne is hanging a string of lights 58 feet long around the three sides of his patio, which is adjacent to his house. The length

podryga [215]

Answer:

The length of the patio is 32 ft and the width is 13 ft

Step-by-step explanation:

see the attached figure to better understand the problem

Let

L ----> the length of his patio

W ---> the width of his patio

we know that

$L+2W=58$ ----> equation A

$L=2W+6$ ----> equation B

substitute equation B in equation A and solve for W

$2W+6+2W=58$

$4W+6=58$

$4W=58-6$

$4W=52$

$W=13\ ft$

Find the value of L

$L=2W+6$ ----> $L=2(13)+6=32\ ft$

therefore

The length of the patio is 32 ft and the width is 13 ft

3 0

3 years ago

What is the slope of the line x = 3?<br> Answer here

diamong [38]

Yo sup??

given line is x=3

this is a line which is parallel to the y axis.

Since it's parallel to the y axis it's slope is infinity.

Hope this helps.

5 0

3 years ago

What is the measure of EFG in circle Obelow?

Mashutka [201]

The two opposite arcs add to the entire circle, 360 degrees, so we must have EFG=360-60=300 degrees.

Answer: C

8 0

3 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$