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d1i1m1o1n [39]
3 years ago
13

Nick will move a storage bin from its current location to the new location shown on the coordinate plane. Describe how Nick coul

d do this, using transformations.
Mathematics
1 answer:
nlexa [21]3 years ago
6 0

Answer:

Move downward by 7 units

Move leftward by 6 units

(x,y) \to (x -6,y-7)

Step-by-step explanation:

Given

See attachment for grid

Required

The transformation from the current location to the new location

To do this, we pick two corresponding points on the current location and the new location.

We have:

A = (3,2) -- Current location

A' = (-6,-5) -- New location

First, move A downwards by 7 units.

The rule to this is:

(x,y) \to (x,y-7)

So, we have:

(3,2) \to (3,2-7)

(3,2) \to (3,-5)

Next, move the above points leftward by 6 units.

The rule to this is:

(x,y) \to (x-6,y)

So, we have:

(3,-5) \to (3-6,-5)

(3,-5) \to (-3,-5)

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german

Step-by-step explanation:

89 multiplied by negative 34 gives a negative answer, since positive multiplied by negative is negative hence,

(89) × (-34) = -3026

4 0
2 years ago
A tent is in the form of a right circular cylinder surmounted by a cone. The volume of the tent can be modeled by the function V
Setler [38]

Answer:

Check this explaination below

Step-by-step explanation:

Check the attached picture

6 0
2 years ago
Find a formula for the linear function with slope -9 and x-intercept 2.
gregori [183]
Hello : 
<span> formula for the linear function with slope -9 and x-intercept 2 is : 
y - 0 = -9(x-2)
y= -9x +18

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4 0
3 years ago
Given that the zeros of a quadratic function are −2 and −5, what is the standard form of the quadratic function? A) f(x) = x2 +
ki77a [65]

Step-by-step explanation:

x = -2 and x = -5

x + 2 = 0 and x + 5 = 0

(x + 2)(x + 5) = 0

x² + 5x + 2x + 10 = 0

x² + 7x + 10 = 0

Option → B

7 0
3 years ago
How do I factor out a constant before factoring out a quadratic? <br>Factor completely: 3w^2-3w-90
pantera1 [17]
3w^2-3w-90 =0 \ \ \:3 \\ \\w^2- w-30 =0 \\ \\a=1 , \ b= -1 , c= -30 \\ \\\Delta =b^2-4ac = (-1)^2 -4\cdot1\cdot (-30) =1+120=121 \\ \\w_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2 }=\frac{ 1-11}{2}=\frac{-10}{2}=-5

w_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2 }=\frac{ 1+11}{2}=\frac{12}{2}=6 \\ \\ Answer:\\ \\ w^2- w-30 =(x+5)(x-6)
 

3 0
3 years ago
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