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3 years ago

The solution to the given system of linear equations lies in which quadrant?

Mathematics

2 answers:

goblinko [34]3 years ago

8 0

Answer:

The solution lies in quadrant IV.

Step-by-step explanation:

Rina8888 [55]3 years ago

5 0

X-3y=6
x+y=2
this is an substitution problem
so first you can do is rewrite the problem by subjection one variable
x=3y+6
then substitute this in the other proble
x+y=2
(3y+6)+y=2
4y+6=2
4y=2-6
4y=-4
y=-1
then substitute the no. in the original equation.
x=3y+6
x=3(-1)+6
x=-3+6
x=3
now you got the intercepts and you draw the line and check.
it's in the IV quadrant

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Part A : Graph the equation.

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The attached figure represents the table to graph the equation and the graph of the equation.

=============================================

Part B : x-intercept

To find x-intercept substitute with y = 0 and solve for x

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4 years ago

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3 years ago

Fill in the missing equation

Valentin [98]

Start with y=mx+b

B is your y intercept
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Now you go back to the equation of a Line y=mx+b
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3 years ago

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Answer:

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