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Over [174]
3 years ago
8

Calculate how much each size per gram, and circle which gives the best value for money. 250g for $2.30, 400g for &3.40, 1Kg

for $5.65
Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0
To do this, we must set up ratios:
Option One:
\frac{2.30}{250g}  \\  \frac{0.0092}{1g}  \\ 0.0092/g
The first options costs only $0.0092/gram (a fraction of a penny)!
Option Two:
\frac{3.40}{400g}  \\  \frac{0.0085}{1g} \\ 0.0085/g
The second option costs only $0.0085/gram (cheaper than option one)!
Option Three: 
This requires a little more work. First, we have to convert the grams into kilograms. For every 1 kg, there is 1,000 g. Therefore, 1,000g costs $5.65. Next, we set up the ratio as usual:
\frac{5.65}{1000g} \\  \frac{0.00565}{1g}  \\ 0.00565/g
The third option costs $0.00565/gram.

Therefore, option three is the cheapest! 

Hope this helps!
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1p
goblinko [34]

Answer:

O 81 km per hour

Explanation

Given parameters:

Number of days traveled  = 3 days

Distance covered on the first day  = 1080km

Time of travel  = 10hrs

Rate of travel  = 108km/hr

Time of travel on second day = 12hrs

Rate of travel  = 90km/hr

Time of travel on third day  = 18hrs

Rate of travel  = 60km/hr

Unknown

Average speed  = ?

To find the average speed, we sum the distances and divide by the sum of the time.

  Average speed  = \frac{Total distance}{total time}

we do not know the second and third distances;

  Distance  = speed x time

D2  = 90 x 12 = 1080km

D3  = 60 x 18  = 1080km

    Now;

  Average speed  = \frac{1080 + 1080 + 1080 }{10 + 12 + 18 }

 

 Average speed  = \frac{3240}{40}   = 81km/hr

The average speed is 81km/hr

6 0
3 years ago
Determine the correct set up for solving the equation using the<br> quadratic formula 4x^2-5=3x+4
slava [35]

You need to subtract everything to the left side and set it equal to zero. Combine like terms.

Then, the coefficient of x^2 is a, the coefficient of x is b, and the constant term is c.

4x^2 - 5 = 3x + 4

4x^2 - 3x - 5 - 4 = 0

4x^2 - 3x - 9 = 0

a = 4; b = -3; c = -9

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

x = \dfrac{-(-3) \pm \sqrt{(-3)^2 - 4(4)(-9)}}{2(4)}

7 0
3 years ago
Determine whether the origin is included in the shaded region and whether the shaded region is above or below the line for the g
just olya [345]

Answer:

The correct option is

The origin is included in the shaded region and the shaded area is below the line.

Step-by-step explanation:

Y>3/2x + 2

Put x=0

Y= 2

(0,2)

Put y=0

X= -4/3

(-4/3,0)

See attached picture for the sketch

3 0
3 years ago
Rafael want to buy the same number of gifts bags and bows gifts bags are sold in packs of 6. Bows are sold in packs of 9. What i
GenaCL600 [577]

Answer:

Rafael should buy 9 gift bags and 6 bows packet so, that she can have SAME NUMBER OF ITEMS, i.e 54.

Step-by-step explanation:

The gift bags are sold in the packs of 6.

So, the number of gift bags in 1 packet  = 6 gift bags

The number of gift bags in 2  packet  = 6 x 2 gift bags  = 12  gift bags

The number of gift bags in 3  packet  = 6 x 3 gift bags  = 18  gift bags

And continuing similarly, we get

The number of gift bags in 9  packet  = 6 x 9 gift bags  = 54 gift bags.. (1)

The bows are sold in the pack of 9.

So, the number of bows in 1 packet  = 9 bows

The number of bows in 2 packet   = 9 x 2 bows  = 18 bows

The number of bows in 3 packet   = 9 x 3 bows  = 27 bows

And continuing similarly, we get

The number of bows in 6  packet  = 9 x 6 bows  = 54 bows... (2)

Here, comparing both equations (1) and (2) , we get

The number of gift bags = 54  = The number of bows.

Hence, Rafael should buy 9 gift bags and 6 packet of bows so, that she can have SAME NUMBER OF ITEMS, i.e 54.

8 0
3 years ago
A glacier advances toward the sea 0.004 mile anually. In 2010 the front of the glacier is 6.9 miles from the mouth of the sea. H
olchik [2.2K]

You know where the glacier is now, and how far it moves in
one year.  The question is asking how close to the sea it will be
after many years.

Step-1 ... you have to find out how many years

Step-2 ... you have to figure out how far it moves in that many years

Step-3 ... you have to figure out where it is after it moves that far

The first time I worked this problem, I left out  the most important
step ... READ the problem carefully and make SURE you know
the real question.  The first time I worked the problem, I thought
I was done after Step-2. 

============================

Step-1:  How many years is it from 2010 to 2030 ?

               (2030  -  2010)  =  20 years .


Step-2:  How far will the glacier move in 20 years ? 

               It moves 0.004 mile in 1 year.

              In 20 years, it moves 0.004 mile 20 times

              0.004 x 20  =  0.08 mile


Step-3: How far will it be from the sea after all those years ?

              In 2010, when we started watching it, it was 6.9 miles
              from the sea.

              The glacier moves toward the sea.
               In 20 years, it will be  0.08 mile closer to the sea.
               How close will it be ?

               6.9 miles  -  0.08 mile  =  6.82 miles  (if it doesn't melt)

7 0
3 years ago
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